Answer:
4054 kcal of heat is released during complete combustion of 354 g of octane.
Explanation:
Heat of combustion of 1 mol of octane is 
kcal
Molar mass of octane = 114.23 g/mol
We know, no. of moles = (mass)/(molar mass)
So, kcal of heat is released during complete combustion of 114.23 g of octane.
So, amount of heat is released during complete combustion of 354 g of octane = 
kcal = 4054 kcal
Hence 4054 kcal of heat is released during complete combustion of 354 g of octane.
Answer:
900 J/mol
Explanation:
Data provided:
Enthalpy of the pure liquid at 75° C = 100 J/mol
Enthalpy of the pure vapor at 75° C = 1000 J/mol
Now,
the heat of vaporization is the the change in enthalpy from the liquid state to the vapor stage.
Thus, mathematically,
The heat of vaporization at 75° C
= Enthalpy of the pure vapor at 75° C - Enthalpy of the pure liquid at 75° C
on substituting the values, we get
The heat of vaporization at 75° C = 1000 J/mol - 100 J/mol
or
The heat of vaporization at 75° C = 900 J/mol
Answer:
you tilt the cylinder at a slight angle so that the metal slides down the sides, rather than drops all it`s weight to the bottom
Answer:The substance is Biodegradable
Explanation:
When something is biodegradable it can be broken down by organical processes or decomposers.
