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olga_2 [115]
3 years ago
10

Calculate the amount of heat needed to convert 190.0 g of ice at -15 °C to water at 35 °C. Cp of ice=2.09J/g*c

Chemistry
1 answer:
salantis [7]3 years ago
6 0

Answer:

The amount of heat required to melt 25 grams of ice is 8,350 Joules or 2,000 calories.

Explanation:

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For the following questions, use a periodic table and your atomic calculations to find the unknown information about each isotop
mafiozo [28]

Answer:

Option B is correct.

4

Explanation:

We know that an atom consist of electron, protons and neutrons. Protons and neutrons are present with in nucleus while the electrons are present out side the nucleus.

All these three subatomic particles construct an atom. A neutral atom have equal number of proton and electron. In other words we can say that negative and positive charges are equal in magnitude and cancel the each other. For example, if neutral atom has 6 protons than it must have 6 electrons. The sum of neutrons and protons is the mass number of an atom while the number of protons are number of electrons is the atomic number of an atom.

In given problem we are given with 2 neutrons of helium. We know that the atomic number of He is 2. Thus Mass number of He is,

Number of neutrons + number of proton

2 + 2 = 4

Thus, option B is correct.

7 0
3 years ago
How many moles is 2.2 x 1023 atoms of Fe?
kow [346]

Answer:

it's 3.77 moles

Explanation:

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4 0
2 years ago
How many quarts are in 0.15 ML
olganol [36]

Answer: divide by 946.353

= 1.58 x 10^-4 or 0.000159

Explanation:

7 0
3 years ago
The arrows in the image show the direction in which carbon is moving Which process of the carbon cycle is indicated
s344n2d4d5 [400]
The carbon cycle involves the circulation of carbon dioxide (CO2<span>) from the atmosphere into plants and other living organisms; the transfer of carbon from these organisms into other temporary storage pools, living or nonliving, containing organic and </span>inorganic<span> carbon compounds; and the return of CO</span>2<span> to the atmosphere </span>
8 0
3 years ago
An 80.0-gram sample of water at 10.0°C absorbs 1680 Joules of heat energy. What is the final temperature of the water? a 50.0°C
ICE Princess25 [194]

Answer:

b)15.0°C

Explanation:

Specific Heat of Water=4.2 J/g°C

This means, that 1 g of Water will take 4.2 J of energy to increase its temperature by 1°C.

∴80 g Water will take 80×4.2 J of energy to increase its temperature by 1°C.

80×4.2 J=336 J

Total Energy Provided=1680 J

The temperature increase=\frac{\textrm{Total energy required}}{\textrm{energy required to increase temperature by one degree}}

Temperature increase=\frac{1680}{336}

=5°C

Initial Temperature =10°C

Final Temperature=Initial + Increase in Temperature

=10+5=15°C

7 0
3 years ago
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