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Answer:
1) Net ionic equation :
2) 0.765 M is the molarity of the carbonic acid solution.
Explanation:
1) In aqueous carbonic acid , carbonate ions and hydrogen ion is present.:
..[1]
In aqueous potassium hydroxide , potassium ions and hydroxide ion is present.:
..[2]
In aqueous potassium carbonate , potassium ions and carbonate ion is present.:
..[3]
From one:[1] ,[2] and [3]:
Cancelling common ions on both sides to get net ionic equation :
2)
To calculate the concentration of acid, we use the equation given by neutralization reaction:
where,
are the n-factor, molarity and volume of acid which is
are the n-factor, molarity and volume of base which is KOH.
We are given:
Putting values in above equation, we get:
0.765 M is the molarity of the carbonic acid solution.
Answer:
0.425 moles of P₂O₅.
Explanation:
As per given balanced equation, four moles of phosphorus reacts with five moles of oxygen to give two moles of P₂O₅.
As given that the initial moles of phosphorus taken = 0.97 moles
moles of phosphorus left after reaction = 0.12 moles
moles of phosphorus reacted = 0.97-0.12 = 0.85 moles
When four moles of P reacts they give two moles of P₂O₅.
when one mole of P will react to give =
0.85 moles of P will react to give = P₂O₅