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NemiM [27]
3 years ago
7

If a 2 cm vector represents speed, and 1 cm equals 5 m/s, how fast is the represented

Physics
1 answer:
Ne4ueva [31]3 years ago
6 0

Answer: 10m/s

Explanation: Since a single vector with length of 1cm expresses 5m/s, the vector which has a length doubled from the original vector should have the speed which is also doubled.

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One type of sunburn occurs on exposure to UV light with a wavelength in the vicinity of 325 nm. What is the energy of a mole of
andrew11 [14]

Answer: Energy of a mole of these photons is 0.368\times 10^6Joules  

Explanation:

The relationship between wavelength and energy of the wave for 1 mole follows the equation:

E=\frac{Nhc}{\lambda}

E= energy

N= avogadros number =6.023\times 10^{23}

\lambda = wavelength of the wave  =325\times 10^{-9}m    1nm=10^{-9}m

h = Planck's constant  = 6.626\times 10^{-34}Js

c = speed of light = 3\times 10^8m/s

E=\frac{6.023\times 10^{23}\times 6.626\times 10^{-34}\times 3\times 10^8m/s}{325\times 10^{-9}m}

E=0.368\times 10^6Joules  

Thus the energy of a mole of these photons is 0.368\times 10^6Joules  

3 0
3 years ago
What determines the chemical properties of an element? A. the number and arrangement of the electrons in an atom B. the number o
bonufazy [111]
<span>The sum of the protons and neutrons in an atom equals the mass number.    </span>
6 0
3 years ago
Read 2 more answers
To estimate the distance in kilometers of a flash of lightning, count the number of seconds between seeing the flash and hearing
Triss [41]

Answer:

Divide by 3

Explanation:

In order to estimate the distance traveled by a lightening flash in kilometers, we follow these simple steps:

  1. Make a count of the number of seconds in between the period a flash occur and the thunder accompanied by the lightening flash is heard.
  2. Dive the total number of seconds by 3 to get the distance traveled by the flash. This is because in order to cover 1 km, it roughly takes 3 seconds.
8 0
3 years ago
How is the direction of light changed when it travels from an optically denser medium to an optically rarer medium????? please a
ANTONII [103]

Answer:

The light bends away from the normal

Explanation:

We can solve the problem by using Snell's law:

n_1 sin \theta_1 = n_2 sin \theta_2

where:

n_1 is the index of refraction of the first medium

n_2 is the index of refraction of the second medium

\theta_1 is the angle of incidence (angle between the incoming ray and the normal to the interface)

\theta_2 is the angle of refraction (angle between the outcoming ray and the normal to the interface)

We can rearrange the equation as

sin \theta_2 = \frac{n_1}{n_2}sin \theta_1

In this problem, light travels from an optically denser medium to an optically rarer medium, so

n_1 > n_2

Therefore, the term \frac{n_1}{n_2} is greater than 1, so

sin \theta_2 > sin \theta_1\\\rightarrow \theta_2 > \theta_1

which means that the angle of refraction is greater than the angle of incidence, and so the light will bend away from the normal.

4 0
3 years ago
What is an ampere?<br><br> NO GUESSING! ANSWERS ONLY!
Igoryamba

Answer:

the SI base unit of electrical current

7 0
3 years ago
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