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4 years ago

6

When a certain gas under a pressure of 4.65 106 Pa at 21.0°C is allowed to expand to 3.00 times its original volume, its final p

ressure is 1.06 106 Pa. What is its final temperature?

1 answer:

Marina CMI [18]4 years ago

7 0

Answer:

-72.0°C

Explanation:

PV = nRT

Since n, number of moles, is constant:

PV / T = PV / T

(4.65×10⁶ Pa) V / (21 + 273.15) K = (1.06×10⁶ Pa) (3V) / T

T = 201.16 K

T = -72.0°C

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<h3>Answer:</h3>

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<h3>Explanation:</h3>

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Answer:

T = 76.39°C

Explanation:

given,

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Answer:

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v t + V t = 40

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4 years ago