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stiv31 [10]
3 years ago
6

HELPPPP PLEASE THIS IS FOR THE CATALYSTS LAB

Chemistry
1 answer:
marishachu [46]3 years ago
4 0

Answer:

the first thing you do is do your experiment then title it. then state the purpose of the experiment. included a summary of the experiment. make a list of the materials you used. present all the steps in order to make the experiment possible. note any changes to the original procedure. this is basically the steps you have to do in order to make your scientific experiment.

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PLEASE HELPPP!!!!!!!!!!!!!!!!!!!!
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3 years ago
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Repeating many forms a crystal structure inside each of these repeated units is the ?
djyliett [7]

Answer:

gggzbjv

Explanation:

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7 0
2 years ago
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This is part two of the other questions
Brums [2.3K]

Answer:

The answer to your question is below

Explanation:

11. Alkali metals

12. Halogens

13. Transition metals

14. Halogens

15. Noble gases

16. Alkaline earth metals

17. Transition metals

18. Alkaline earth metals

19. Transition metals

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21.- Periods

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8 0
3 years ago
Draw the major organic substitution product(s) for (2R,3S)-2-bromo-3-methylpentane reacting with the given nucleophile. Indicate
Andrew [12]

Answer:

(2R,3S)-2-ethoxy-3-methylpentane

and

(2S,3S)-2-ethoxy-3-methylpentane

Explanation:

For this case, we will have  CH_3CH_2O^- as nucleophile. Also, this compound is also in excess. So, we will have as solvent CH_3CH_2OH a protic solvent. Therefore the Sn1 reaction would be favored.

The first step would be the carbocation formation followed by the attack of the nucleophile. In this case both isomers would be produced: R and S (see figure).

7 0
2 years ago
A solution with a ph of 4 has _________ the concentration of h+ present compared to a solution with a ph of 5.
Marina CMI [18]
<span>A solution with a pH of 4 has ten times the concentration of H</span>⁺<span> present compared to a solution with a pH of 5.
</span>pH <span>is a numeric scale for the acidity or basicity of an aqueous solution. It is  the negative of the base 10 logarithm of the molar concentration of hydrogen ions.
</span>[H⁺] = 10∧-pH.
pH = 4 → [H⁺]₁ = 10⁻⁴ M = 0,0001 M.
pH = 5 → [H⁺]₂ = 10⁻⁵ M = 0,00001 M.
[H⁺]₁ / [H⁺]₂ = 0,0001 M / 0,00001 M.
[H⁺]₁ / [H⁺]₂ = 10.
7 0
3 years ago
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