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2 years ago

A temperature of a 0.349 kg sample of copper decreases from 87.0 °C to 21.0 °C. How much heat

Physics

1 answer:

Arte-miy333 [17]2 years ago

7 0

We have that heat flow out of the copper sample is mathematically given as

Q=8.86809J

Question Parameters

A temperature of a 0.349 kg sample of copper
decreases from 87.0 °C to 21.0 °C.

Endothermic Reaction

It is common knowledge that an endothermic reaction is one where the system absorbs heat energy from the environs.

Exothermic Reaction

An exothermic reaction is one where the system releases heat energy to the environs.

Generally the equation for Heat is mathematically given as

$Q=mCdt\\\\Therefore\\\\Q=0.349*0.385*(87-21)$

Q=8.86809J

For more information on temperature visit

brainly.com/question/15267055

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3 years ago

A wheel rotating about a fixed axis with a constant angular acceleration of 2.0 rad/s2 starts from rest at t = 0. The wheel has

irga5000 [103]

Answer:

The total linear acceleration is approximately 0.246 meters per square second.

Explanation:

The total linear acceleration ( $a$ ) consist in two components, radial ( $a_{r}$ ) and tangential ( $a_{t}$ ), in meters per square second:

$a_{r} = \omega^{2}\cdot r$ (1)

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$a = \sqrt{a_{r}^{2}+a_{t}^{2}}$ (3)

Where:

$r$ - Radius of the wheel, in meters.

$\omega$ - Angular speed, in radians per second.

$\alpha$ - Angular acceleration, in radians per square second.

Given that wheel accelerates uniformly, we use the following kinematic equation:

$\omega = \omega_{o}+ \alpha\cdot t$ (4)

Where:

$\omega_{o}$ - Initial angular speed, in radians per second.

$t$ - Time, in seconds.

If we know that $r = 0.1\,m$ , $\alpha = 2\,\frac{rad}{s^{2}}$ , $\omega_{o} = 0\,\frac{rad}{s}$ and $t = 0.60\,s$ , then the total linear acceleration is:

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$a_{r} = \omega^{2}\cdot r$

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$a_{t} = 0.2\,\frac{m}{s^{2}}$

$a = \sqrt{a_{r}^{2}+a_{t}^{2}}$

$a \approx 0.246\,\frac{m}{s^{2}}$

The total linear acceleration is approximately 0.246 meters per square second.

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2 years ago

What is the energy in joules of a photon with a frequency of 3.16e 12 s-1?

erica [24]

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Substitute the values into the expression:
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3 years ago

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Answer:

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Explanation:

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