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3 years ago

The work required to move a box a particular distance is 300 J. How much power is required to move the box in 3 seconds?

Physics

1 answer:

Afina-wow [57]3 years ago

7 0

Given:

Work = 300 Joule

time = 3 second

To find:

Power required to move a box = ?

Formula used:

P = $\frac{W}{t}$

Where P = power required to move box

W = work done to move the box

t = time taken to move the box

Solution:

Power required to move the box is given by,

P = $\frac{W}{t}$

Where P = power required to move box

W = work done to move the box

t = time taken to move the box

P = $\frac{300}{3}$

P = 100 Watt

Thus, Power required to move the box for 3 second is 100 Watt.

Hence, Option (B) is correct.

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Mashutka [201]

Answer:

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4 years ago

IP Standing side by side, you and a friend step off a bridge at different times and fall for 1.6 s to the water below. Your frie

ratelena [41]

The distance to the water is the same for both ... call it s meters

They both take 1.6 s to reach the water ... so t = 1.6 seconds

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Just consider the vertical motion and take DOWN as the positive direction

a = 9.8 m/s²

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s = 0 + (1/2) * 9.8 * 1.6²

s = 12.5 m ←←← Edit: Forgot to say ... that's how high the bridge is above the water

Now get the time it takes the first jumper to reach 1.8 m:

s = v(i)t + (1/2)at²

1.8 = 0 + 4.9t²

t = 0.61 s

so when the 2nd person jumps it takes the first person another 1.6 - 0.61 = 0.99 s to reach the water

Now find how far the 2nd jumper falls in 0.99 s:

s = 0 + 4.9 * 0.99²

s = 4.8 m

so the separation distance between the two jumpers when the 1st jumper hits the water is 12.5 - 4.8 = 7.7 m

6 0

3 years ago

A cord is wrapped around the outer surface of the 8-kg disk. If a force of F = (1⁄4u2) N, where u is in radians, is applied to t

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