Question

Factor completely 8x^2-6x-2x^3

Answer 1

Answer:

2x(x-3)(-x+1)

Step-by-step explanation:

Factor 2x from everything -> 2x(4x-3-x^2)

Reorder the terms -> 2x(-x^2+4x-3)

Write 4x as a sum -> 2x(-x^2+3x+x-3)

Factor out -x from -x^2+3x looks like -> 2x(-x(x-3)+x-3)

Factor out x-3 from the expression -> 2x(x-3)(-x+1)

Answer 2

Answer:

$\displaystyle \large \boxed{ - 2x( x - 3)(x - 1)}$

Step-by-step explanation:

We are given the expression:

$\displaystyle \large{8 {x}^{2} - 6x - 2 {x}^{3}}$

Notice how the expression has same x-term but not same degree, we can common factor out the x.

Factor using LCF (Least Common Factor which is 2x because 8 and 6 are multiples of 2.)

Therefore:-

$\displaystyle \large{2x(4x - 3 - {x}^{2}) }$

Inside the brackets, we can still factor. First, arrange the expression:-

$\displaystyle \large{2x( - {x}^{2} + 4x - 3) }$

Factor -1 or negative sign out of the expression:

$\displaystyle \large{ - 2x( {x}^{2} - 4x + 3) }$

Factor x^2-4x+3 using two brackets.

What two numbers add/subtract each others and yield -4? The two numbers must multiply and yield 3 as well.

• -3 and -1 seem right value because -3-1 = -4 and -3(-1) is 3.

Thus:-

$\displaystyle \large{ - 2x( x - 3)(x - 1)}$

And we're done!