since it has a diameter of 28, then its radius must be half that or 14.
![\textit{area of a circle}\\\\ A=\pi r^2~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ r=14 \end{cases}\implies A=\pi (14)^2\implies A=196\pi ~\hfill \stackrel{\stackrel{semi-circle}{half~that}}{98\pi }](https://tex.z-dn.net/?f=%5Ctextit%7Barea%20of%20a%20circle%7D%5C%5C%5C%5C%20A%3D%5Cpi%20r%5E2~~%20%5Cbegin%7Bcases%7D%20r%3Dradius%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20r%3D14%20%5Cend%7Bcases%7D%5Cimplies%20A%3D%5Cpi%20%2814%29%5E2%5Cimplies%20A%3D196%5Cpi%20~%5Chfill%20%5Cstackrel%7B%5Cstackrel%7Bsemi-circle%7D%7Bhalf~that%7D%7D%7B98%5Cpi%20%7D)
Answer:
102 sqaure feet
Step-by-step explanation:
Answer:
You start at -9
-Open circle
-shade towards the right (where all the positive numbers are)
Open circle - ones that don't have a greater than or equal to. If it does then it's a closed one.
Shade towards the right cause y is less than 9
Answer:
c
Step-by-step explanation:
i did it in a test and i used a calculator
Hey There :)
This is because one is half of two. You could also multiply 2 * 0.5= 1, 0.5 represents

and two is the whole number. This is how

of two equals one.
Have A Brainly Day :)