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Ugo [173]
3 years ago
5

The solubility product constant for mg(oh2(s is 1.2x10^-11 calculate solubility of magnesium hydroxide in mol/l

Chemistry
1 answer:
LekaFEV [45]3 years ago
8 0
27,632 would be the answer
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Three isotopes of sulfur are sulfur-32, sulfur-33, and sulfur-34. write the complete symbol for each isotope, including the atom
Maurinko [17]
Sulfur is an element in the periodic table that has a chemical symbol of S. This element is the 16th element in periodic table. This means that the atomic number or number of protons in the nucleus of the atom is equal to 16.

The number following the name of the element is the mass number. The following are the complete symbol that are arranged as follows:
 chemical symbol - atomic number - mass number

*Sulfur-32
         S - 16 - 32

*Sulfur-33
        S - 16 - 33

*Sulfur-34
        S - 16 - 34
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3 years ago
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What are the two measurement systems the thermometer uses? Which one is most commonly used for science? Why?
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4 years ago
What are three forms of the element carbon?
german

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There are at least eight forms of carbon: amorphous, graphite, diamond, fullerenes, aggregated diamond nanorods, carbon nanofoam, glassy carbon, and linear acetylenic carbon.

Explanation:

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3 years ago
The _________ indicates that 70% of the Sun's radiation is contained on Earth and 30% is reflected back into space.
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GIVING BRAINLIEST One mole of hydrogen gas (H2), reacts with one mole of bromine Br2(g) to produce 2 moles of hydrogen bromide g
JulsSmile [24]

Answer:

The equation to show the the correct form to show the standard molar enthalpy of formation:

\frac{1}{2}H_2(g) +\frac{1}{2}Br_2(l)\rightarrow HBr(g) ,\Delta H_{f}^o= -36.29 kJ

Explanation:

The standard enthalpy of formation or standard heat of formation of a compound is the change of enthalpy during the formation of 1 mole of the substance from its constituent elements, with all substances in their standard states.

Given, that 1 mole of H_2 gas and 1 mole of Br_2 liquid gives 2 moles of HBr gas as a product.The reaction releases 72.58 kJ of heat.

H_2(g) + Br_2(l)\rightarrow 2HBr(g) ,\Delta H_{f}^o= -72.58kJ

Divide the equation by 2.

\frac{1}{2}H_2(g) +\frac{1}{2}Br_2(l)\rightarrow HBr(g) ,\Delta H_{f}^o= -36.29 kJ

The equation to show the the correct form to show the standard molar enthalpy of formation:

\frac{1}{2}H_2(g) +\frac{1}{2}Br_2(l)\rightarrow HBr(g) ,\Delta H_{f}^o= -36.29 kJ

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3 years ago
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