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Ugo [173]
3 years ago
5

The solubility product constant for mg(oh2(s is 1.2x10^-11 calculate solubility of magnesium hydroxide in mol/l

Chemistry
1 answer:
LekaFEV [45]3 years ago
8 0
27,632 would be the answer
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What must the melting point of the mold be compared to the temperature at which class get soft and why
stiv31 [10]

The answer is that the mold melting point must be higher then molten glass, otherwise the mold would melt when molten glass is poured into it .


I hope this helps :)

7 0
3 years ago
Name two compounds with more exothermic lattice energies than scandium oxide and justify your choice.
N76 [4]

Answer:

1 . Al_2O_3

2. TiO_2

Explanation:

The more stable the ionic compound, the more is it lattice energy.

  • The more the charge on the cation and the anion, the greater is the lattice energy.
  • The less the size of the cation and the anion, the greater is the lattice energy.

Scandium oxide (Sc_2O_3) is an oxide in which Sc^{3+} behaves as cation and O^{2-} behaves as anion.

The compounds which has higher lattice energy than scandium oxide are:

1 . Al_2O_3

This is because the charge are same on the cation and the anion as in the case of the Scandium oxide but the size of the cation Al^{3+} is smaller than Sc^{3+}. Thus, this corresponds to higher lattice energy.

2. TiO_2

This is because the charge on the cation Ti^{4+} is greater than that of Sc^{3+} and also the size of the cation Ti^{4+} is smaller than Sc^{3+}. Thus, this corresponds to higher lattice energy.

3 0
3 years ago
Helpppppppppppppppppppppppppppp
worty [1.4K]

Answer:

evaporation or water runoff that's my tips

rain or thunder storm

6 0
2 years ago
Read 2 more answers
Is matter lost when a candle is burned
zlopas [31]
No it is redistributed and the state changes to gas and liquid
5 0
3 years ago
Read 2 more answers
Given 2.14g of B2H6
Shkiper50 [21]

Answer:

(A) is 0.0773 mol B2H6

(C) is 2.79 x 10^23 H atoms

Explanation:

Questions (A) and (B) are the same.

2.14 g B2H6 x (1 mol B2H6/27.668g B2H6) = 0.0773 mol B2H6 (A)

<u>27.668 is the molar mass of B2H6 calculated from the period table: </u>

(2 x 10.81) + (6 x 1.008) = 27.668

1.008 is the mass of H and 10.81 is the mass of B

(C)

0.0773 mol B2H6 x (6 mol H/ 1 mol B2H6) x (6.022 x 10^23 H atoms/1 mol H)

= 2.79 x 10^23 hydrogen atoms

Further Explanation:

  • For every 1 mol of B2H6, there are 6 moles of H (indicated by the subscript)
  • 6.022 x 10^23 is Avogrado's number and it equals to 1 mol of anything
  • Avogrado's number can be in units of atoms, molecules, or particles
5 0
3 years ago
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