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Ugo [173]
3 years ago
5

The solubility product constant for mg(oh2(s is 1.2x10^-11 calculate solubility of magnesium hydroxide in mol/l

Chemistry
1 answer:
LekaFEV [45]3 years ago
8 0
27,632 would be the answer
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4.The scientific method is ________________ reasoning. You can make ______________ explanations for something that you are obser
Novay_Z [31]

Answer:

The scientific method is a system of reasoning. You can make reasonable explanations for something that you are observing in the world.

Explanation:

4 0
3 years ago
The burning of coal, a fossil fuel, produces water and carbon dioxide. How is this similar to cellular respiration?
Mrac [35]

Answer:

I think the answer is C but you might need a second opinion on this answer

6 0
3 years ago
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Complete the reaction by writing the formulas of the products. CH 3 COOH + NH 3 − ⇀ ↽ − CH_{3}COONH_{4}^{+} CH 3 COONH + 4 The K
cricket20 [7]

Answer:

Products are favored.

Explanation:

The acid-base reaction of CH₃COOH (acid) with NH₃ (base) produce:

CH₃COOH + NH₃ ⇄ CH₃COO⁻ +  NH₄⁺ Kr = ?

It is possible to know Kr of the reaction by the sum of acidic dissociations of the half-reactions. That is:

CH₃COOH ⇄ CH₃COO⁻ + H⁺ Ka = 1.8x10⁻⁵

NH₃ + H⁺ ⇄ NH₄⁺ 1/Ka = 1/ 5.6x10⁻¹⁰ = 1.8x10⁹

___________________________________

CH₃COOH + NH₃ ⇄ CH₃COO⁻ +  NH₄⁺ Kr =  1.8x10⁻⁵×1.8x10⁹ = <em>3.2x10⁴</em>

<em> </em>

As Kr is defined as:

Kr =  [CH₃COO⁻] [NH₄⁺] / [CH₃COOH] [NH₃]

And Kr is > 1  

[CH₃COO⁻] [NH₄⁺] > [CH₃COOH] [NH₃],

showing <em>products are favored</em>.

4 0
3 years ago
It didn't have science but it is a science question. The average, year-after-year conditions of temperature, precipitation, wind
larisa86 [58]
Hey there,

Question : <span>The average, year-after-year conditions of temperature, precipitation, winds, and cloud in an area are known as its?

Answer : A, climate

Hope this helps :))

<em>~Top♥</em>
</span>
6 0
3 years ago
Using this equation, m1v2=m2v2 , calculate the diluted molarity of 100 mL of a 0.5 M solution when 50 mL of
geniusboy [140]

The molarity of the diluted solution is 0.33 M

From the question given above, the following data were obtained:

Molarity of stock solution (M₁) = 0. 5 M

Volume of stock solution (V₁) = 100 mL

Volume of diluted solution (V₂) = 100 + 50 = 150 mL

<h3>Molarity of diluted solution (M₂) =? </h3>

The molarity of the diluted solution can be obtained by using the dilution formula as illustrated below:

<h3>M₁V₁ = M₂V₂</h3>

0.5 × 100 = M₂ × 150

50 = M₂ × 150

Divide both side by 150

M₂ = 50 / 150

<h3>M₂ = 0.33 M</h3>

Therefore, the molarity of the diluted solution is 0.33 M

Learn more: brainly.com/question/24625656

8 0
2 years ago
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