The solubility product constant for mg(oh2(s is 1.2x10^-11 calculate solubility of magnesium hydroxide in mol/l
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Answer:
Explanation:
Molarity is a measure of concentration in moles per liter.
<h3>1. Grams to Moles </h3>The first step is to convert the amount of grams given to moles. The molar mass is used. This found on the Periodic Table and it's the same value as the atomic mass, but the units are grams per mole.
We have 224 grams of KOH. Look up the molar masses for the individual elements.
- Potassium (K): 39.098 g/mol
- Oxygen (O): 15.999 g/mol
- Hydrogen (H): 1.008 g/mol
Since the compound's formula has no subscripts, 1 formula unit has 1 atom of each element. We can simply add the molar masses together to find KOH's molar mass.
- KOH: 39.098 + 15.999 + 1.008=56.105 g/mol
Use this number as a ratio.
Multiply by the value we are converting: 224 g KOH
Flip the ratio so the units of grams KOH cancel.
Remember molarity is moles per liter.
We just calculated the moles and we know there are 2 liters of solution.
First, let's round. The original values have 3 and 1 significant figures. We go with the lowest number: 1. For the number we found, that is the ones place.
- 1.<u>9</u>96257018
The 9 in the tenths place tells us to round to 1 up to a 2
Next, convert units. 1 mole per liter is equal to 1 molar or M.
The molarity of the solution is <u>2 M KOH</u>