![arc \ length \ of \ BD = \pi r ( \frac{\angle BPD}{180} ) \\ \\ \angle BPD=\angle APC=92^o \ \ \text{[vertical angle]} \\ \\ arcBD= \pi *8 *\frac{92}{180} \approx 4.09 \pi \ in \approx12.85 in ](https://tex.z-dn.net/?f=arc%20%5C%20length%20%5C%20of%20%5C%20BD%20%3D%20%5Cpi%20r%20%28%20%5Cfrac%7B%5Cangle%20BPD%7D%7B180%7D%20%29%20%20%5C%5C%20%20%5C%5C%20%5Cangle%20BPD%3D%5Cangle%20APC%3D92%5Eo%20%5C%20%5C%20%5Ctext%7B%5Bvertical%20angle%5D%7D%20%5C%5C%20%20%5C%5C%20arcBD%3D%20%5Cpi%20%2A8%20%2A%5Cfrac%7B92%7D%7B180%7D%20%20%5Capprox%204.09%20%5Cpi%20%20%5C%20in%20%5Capprox12.85%20in%0A)
Answer: ≈4.09π in. ≈12.85 in.
I would say to round 48 to 50 and then multiply 50 x 3=150 or if you do 48x3=144 then estimate it to about 140
The answer would be B because (x,y) x is the domain and y is the range
Hope this helps
Have a great day/night
Answer: divide the big number by 2
Step-by-step explanation: dude it literally tells you the answer almost xD jsut divide the big number by 2
