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Nikitich [7]
3 years ago
9

engineering controls are devices such as self sheathing needles and sharps containers to block or eliminate the sharp risk. true

or false?
Engineering
1 answer:
Paladinen [302]3 years ago
6 0

Answer:

yes

Explanation:

The 1991 standard states, "engineering and work practice controls shall be used to eliminate or minimize employee exposure." The revision defines Engineering Controls as "controls (e.g., sharps disposal containers, self-sheathing needles, safer medical devices, such as sharps with engineered sharps injury protections ...

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Motorcycles are extremely hard to see if they are _______. powered by quiet motors approaching from the side driving on the shou
Assoli18 [71]

Answer: uve earned 5 b point for helping us

Explanation:well know I'm not helping u

7 0
3 years ago
In manufacturing a particular set of motor shafts, only shaft diameters of between 38.00 and 37.50 mm are usable. If the process
Masteriza [31]

Answer:

P(37.5

And we can find this probability with this difference:

P(-2.5

And in order to find these probabilities we can use tables for the normal standard distribution, excel or a calculator.  

P(-2.5

So then the percentage usable are 94,6%

Explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the diameters of a population, and for this case we know the distribution for X is given by:

X \sim N(37.8,0.12)  

Where \mu=37.8 and \sigma=0.12

We are interested on this probability

P(37.5

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(37.5

And we can find this probability with this difference:

P(-2.5

And in order to find these probabilities we can use tables for the normal standard distribution, excel or a calculator.  

P(-2.5

So then the percentage usable are 94,6%

4 0
3 years ago
2 times 4 - 3 times 5​
Papessa [141]

Answer:

<h3>The answer is - 7</h3>

Explanation:

The statement above is written as

2 × 4 - 3 × 5

8 - 15

= - 7

Hope this helps you

4 0
4 years ago
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Which of the following is not an example of heat generation? a)- Exothermic chemical reaction in a solid b)- Endothermic Chemica
Sav [38]

Answer:

b) Endothermic Chemical Reactions in a solid

Explanation:

Endothermic reactions consume energy, which will result in a cooler solid when the reaction finishes.

8 0
3 years ago
it is used to meusure the amount of electric current. A.clamp meter. B .micrometer C steel rule D. electric meter​
Marianna [84]

Answer:

<em>Option D </em>

<em>Electric meter is used to </em><em>measure</em><em> the amount of electric current</em>

6 0
3 years ago
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