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Marina86 [1]
3 years ago
6

Assume there exists some hypothetical metal that exhibits ferromagnetic behavior and that has (1) a simple cubic crystal structu

re, (2) an atomic radius of 0.154 nm, and (3) a saturation flux density of 0.83 tesla. Determine the number of Bohr magnetons per atom for this material. A: What is the volume, in m3, for this unit cell?B: How many atoms are there per m3 in this material?C: What is the number of Bohr magentons per atom for this material?
Engineering
1 answer:
scoray [572]3 years ago
3 0

Answer:

a. 2.9218x10^(-29) m^3

b. 7.1230x10^(28) atoms/m^3

c. 2.0812 BM/atom

Explanation:

Atomic radius r = 0.154 nm

saturation flux density Bs = 0.83 tesla

- the formula for the volume of the simple cubic crystal (Vc) = a^3 = (2r)^3

= (2 x 0.154x10^-9)^3

= 2.9218x10^-29 m^3

- The formula for the Bohr magneton per atom with respect to VC, Bs, permeability of the vacuum Uo and magnetic moment per Bohr magneton Ub is;

Bohr magneton per atom nb = (Bs x VC) / (Ub x Uo)

                                    = (0.83 x 2.9218x10^-29) / (9.27x10^-24) x(1.257x10^-6)

                                    = 2.4251x10^-29 / 1.1652x10^-29

                                    = 2.0812 BM/atom

- Number of atoms per Vc, N = nb / Vc

                                              = 2.0812 / 2.9218x10^-29 = 7.1230x10^28 atoms

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Create a project named CarDealer that contains a Form for an automobile dealer. Include options for at least three car models. A
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Answer:

/****************** The code for a form application that uses radioButtons * *and displays new form based on the user selection *****************/

Using system;

Using system windows forms;

namespace CarDealer

{

Public partial class Form1 : Form

{

public Form1()

{

//default constructor to initialize components

InitializeComponent();

}

//when user clicks on the details button

private void detail_Click

(Object sender, EventArgs e)

{

if (model1,Checked)

{

Forms2 f = new Form2()

f.ShowDialog()

model1.Checked = false

}

if (model2.Checked)

{

Form3 f = new Form3();

f.ShowDialog();

model2.Checked = false;

}

if (model3.Checked)

{

Form4 f = new Form4();

f.ShowDialog();

model3.Checked = false;

}

}

}

}

Explanation:

Program plan

- Design form: Place label controls with text as select car model and one empty label control to display total price. Change front type and size from each other labels properties window.

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- Add button with text View Details.

- Add 3 new windows form from project menu for each car model.

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7 0
3 years ago
1.The moist unit weights and degrees of saturation of a soil are given: moist unit weight (1) = 16.62 kN/m^3, degree of saturati
alexandr1967 [171]

Answer:

Gs = 2.647

e = 0.7986

Explanation:

We know that moist unit weight of soil is given as

\gamma_m \ or\ bulk\ density = \frac{(Gs+Se)\times \gamma_w}{(1+e)}

where,  \gamma_m = moist unit weight of the soil

Gs = specific gravity of the soil

S = degree of saturation

e = void ratio

\gamma_w = unit weight of water = 9.81 kN/m3

From data given we know that:

At 50% saturation,\gamma_m = 16.62 kN/m3

puttng all value to get Gs value;

16.62= \frac{(Gs+0.5*e)\timees 9.81}{(1+e)}

Gs - 1.194*e = 1.694 .........(1)

for saturaion 75%, unit weight = 17.71 KN/m3

17.71 = \frac{(Gs+0.75*e)\times 9.81}{(1+e)}

Gs - 1.055*e = 1.805 .........(2)

solving both  equations (1) and (2), we obtained;

Gs = 2.647

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Answer:

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