CAN SOMEONE GIVE ME AND ANSWER AND EXPLANTION FOR ALL THESE QUESTIONS PLEASE, I AM STRUGGLING
1 answer:
Answer:
13.) 44V
14.) 66V
15.) 9A
16.) 12V
Explanation:
Concepts you need to know:
1. Resistors in series can be combined by summing up their values.
2. The current always stays the same when the resistors are in series.
3. Ohms Law:
13.) We know that the resistors are in series so we can combine them into a single big resistor. We got R₄ = R₃+R₂+R₁ = 2+4+5 = 11Ω.
We also know that current is the same in a series of resistors, so there's 4A going through the entire circuit.
Using ohm's law, we can calculate V = IR = (4)(11) = 44V
14.) Same explanation as part (13). Except now the current is I=6A. All we have to do is to replace the previous I=4 to I=6.
V = IR = (6)(11) = 66V
15.) Again, we know that current is the same when resistors are in series. So if you can find the current through R1 then that's the same current throughout the entire circuit.
We're given E₁=18V, so...
I = V/R = E₁/R₁ = 18/2 = 9A
this means 9A will also flow through R₃.
16.) Same concept as part (15). We know that E₃=15V, so lets find the current.
I = V/R = E₃/R₃ = 15/5 = 3A
Since current is same throughout the circuit, I₁=3A as well. Use this to calculate the voltage through R₁.
V = IR = I₁R₁ = (3)(2) = 6V
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Answer:
The thickness of the material is 6.23 cm
Explanation:
Given;
quantity of heat, Q = 6706.8 *10⁶ kcal
duration of the heat transfer, t = 5 months
thermal conductivity of copper, k = 385 W/mk
outside temperature of the heater, T₁ = 30° C
inside temperature of the heater, T₂ = 50° C
dimension of the rectangular heater = 450 cm by 384 cm
1 kcal = 1.163000 Watt-hour
6706.8 *10⁶ kcal = 7800008400 watt-hour
I month = 730 hours
5 months = 3650 hours
Rate of heat transfer, P =
Rate of heat transfer,
where;
P is the rate of heat transfer (W)
k si the thermal conductivity (W/mk)
ΔT is change in temperature (K)
A is area of the heater (m²)
L is thickness of the heater (m)
L = 6.23 cm
Therefore, the thickness of the material is 6.23 cm
Answer:
The total force resisted by the flange bolts is 163.98 N
Explanation:
Solution
The first step is to find the pipe cross section at the inlet section
Now,
A₁ = π /4 D₁²
D₁ = diameter of the pipe at the inlet section
Now we insert 8 cm for D₁ which gives us A₁ = π /4 D (8)²
=50.265 cm² * ( 1 m²/100² cm²)
= 5.0265 * 10^⁻³ m²
Secondly, we find cross section area of the pipe at the inlet section
A₂ = π /4 D₂²
D₂ = diameter of the pipe at the inlet section
Now we insert 5 cm for D₁ which gives us A₁ = π /4 D (5)²
= 19.63 cm² * ( 1 m²/100² cm²)
= 1.963 * 10^⁻³ m²
Now,
we write down the conversation mass relation which is stated as follows:
Q₁ = Q₂
Where Q₁ and Q₂ are both the flow rate at the exist and inlet.
We now insert A₁V₁ for Q₁ and A₂V₂ for Q₂
So,
V₁ and V₂ are defined as the velocities at the inlet and exit
We now insert 5.0265 * 10^⁻³ m² for A₁ 5 m/s for V₁ and 1.963 * 10^⁻³ m² for A₂
= 5.0265 * 5 = 1.963 * V₂
V₂ = 12.8 m/s
Note: Kindly find an attached copy of the part of the solution to the given question below
