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givi [52]
3 years ago
13

A 7.47 g sample of calcium carbonate [CaCO3 (s)] absorbs 85 J of heat, upon which the temperature of the sample increases from 2

1 °C to 34.9 °C. What is the specific heat of calcium carbonate?
A 0.82
B 8800
C 46
D 160
E -0.82
Chemistry
1 answer:
Alex_Xolod [135]3 years ago
7 0

Answer:

Specific heat of calcium carbonate(C) = 0.82 (Approx)

Explanation:

Given:

Energy absorbs (q) = 85 J

Change in temperature (Δt) = 34.9 - 21 = 13.9°C  

Mass of calcium carbonate = 7.47 g

Find:

Specific heat of calcium carbonate(C)

Computation:

Specific heat of calcium carbonate(C) = q / m(Δt)

Specific heat of calcium carbonate(C) = 85 / (7.47)(13.9)

Specific heat of calcium carbonate(C) = 85 / 103.833

Specific heat of calcium carbonate(C) = 0.8186

Specific heat of calcium carbonate(C) = 0.82 (Approx)

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5 0
3 years ago
4.80 x 10^25 formula units pf calcium iodide (Cal2) will have what mass?
maw [93]

Answer:

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Explanation:

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∴ mol CaI2 = (4.80 E25 units )×(mol/6.022 E23 units) = 79.708  mol CaI2

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7 0
3 years ago
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miskamm [114]

Answer:

b

Explanation:

6 0
3 years ago
Read 2 more answers
The empirical formula of a compound is CH2O and its molecular weight is 90.09 g/mol. Determine the molecular formula.
Pachacha [2.7K]

Answer : The molecular formula of the compound will be, C_{3}H_{6}O_3

Explanation :

Empirical formula : It is the simplest form of the chemical formula which depicts the whole number of atoms of each element present in the compound.  

Molecular formula : it is the chemical formula which depicts the actual number of atoms of each element present in the compound.  

For determining the molecular formula, we need to determine the valency which is multiplied by each element to get the molecular formula.

The equation used to calculate the valency is :

n=\frac{\text{molecular mass}}{\text{empirical mass}}

As we are given that the empirical formula of a compound is CH_2O and the molar mass of compound is, 90.09 gram/mol.

The empirical mass of CH_2O = 1(12) + 2(1) + 1(16) = 30 g/eq

n=\frac{\text{molecular mass}}{\text{empirical mass}}

n=\frac{90.09}{30}=3

Molecular formula = (CH_2O)_n=(CH_2O)_3=C_{3}H_{6}O_3

Thus, the molecular formula of the compound will be, C_{3}H_{6}O_3

7 0
4 years ago
(b) What amount (mol) of H₂ can be produced from the given mass of H₂O?
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