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givi [52]
3 years ago
13

A 7.47 g sample of calcium carbonate [CaCO3 (s)] absorbs 85 J of heat, upon which the temperature of the sample increases from 2

1 °C to 34.9 °C. What is the specific heat of calcium carbonate?
A 0.82
B 8800
C 46
D 160
E -0.82
Chemistry
1 answer:
Alex_Xolod [135]3 years ago
7 0

Answer:

Specific heat of calcium carbonate(C) = 0.82 (Approx)

Explanation:

Given:

Energy absorbs (q) = 85 J

Change in temperature (Δt) = 34.9 - 21 = 13.9°C  

Mass of calcium carbonate = 7.47 g

Find:

Specific heat of calcium carbonate(C)

Computation:

Specific heat of calcium carbonate(C) = q / m(Δt)

Specific heat of calcium carbonate(C) = 85 / (7.47)(13.9)

Specific heat of calcium carbonate(C) = 85 / 103.833

Specific heat of calcium carbonate(C) = 0.8186

Specific heat of calcium carbonate(C) = 0.82 (Approx)

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0.33 moles = 66.83g

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For which enzyme are nucleotides the substrate? a)l Protease b) Ligase c) Ribosome d) DNA polymerase
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We refer to a substance as a substrate when another substance is added to it. It is defined differently in several sciences. It is a molecule or substance that, when exposed to a catalyst, enzyme, or inhibitor, causes a chemical reaction. In the field of material sciences, the term "substrate" is widely used to describe the base material on which various processing operations are carried out with predetermined reaction parameters to produce additional layers and films, such as coatings. As a result, there are numerous definitions available in the literature, depending on the substrate's applications and area of study. A molecule with which an enzyme interacts is known as a substrate. A substrate is put into the active site of the enzyme, which is where weak bonds between two molecules might form. The substrate reacts under the pressure of the enzyme, forming an enzyme substrate complex that is the product of the intended reaction. The bonds that form between the substrate and the enzyme are what induce the conformational shift, or shape change, in the enzyme.

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7 0
1 year ago
A mixture consisting of only iron(II) chloride (FeCl2) and chromium(II) chloride (CrCl2) weighs 1.0294 g. When the mixture is di
LenKa [72]

Answer:

Mass FeCl2 = 0.0333g

Mass CrCl2 = 0.9961g

Explanation:

To solve this problem. The first equation we can write is:

Mass FeCl2 + Mass CrCl2 = 1.0294g <em>(1)</em>

Now, the Chlorides of FeCl2 and CrCl2 react producing 2.3609g of AgCl

Using molar mass of these species (126.75g/mol, 122.9g/mol, 143.32g/mol, respectively), you can write the equation:

2Mass FeCl2 / 126.75 + 2Mass CrCl2 / 122.9 = 2.3609/143.32

<em>That is: Moles Chloride before = Moles Chloride in AgCl after reaction</em>

7.8895x10⁻³Mass FeCl2 + 0.0162734MassCrCl2 = 0.016473 <em>(2)</em>

<em></em>

Replacing (1) in (2):

7.8895x10⁻³ (1.0294g - MassCrCl2) + 0.0162734MassCrCl2 = 0.016473

8.12145x10⁻³ -7.8895x10⁻³MassCrCl2 + 0.0162734Mass CrCl2 = 0.016473

8.3839x10⁻³ MassCrCl2 = 8.35155x10⁻³

Mass CrCl2 = 0.9961g

And:

Mass FeCl2 = 1.0294g - 0.9961g

Mass FeCl2 = 0.0333g

3 0
3 years ago
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