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kodGreya [7K]
3 years ago
8

In the diagram attached inside, if electrons flow from the right half-cell to the left one through the wire, which of the follow

ing statements is true?
A. The metal strip on the right has a lower activity than the one on the left.

B. The activities of both metal strips are equal.

C. The metal strip on the left has a lower activity than the one on the right.
Chemistry
2 answers:
Ahat [919]3 years ago
7 0

Answer: A.

Explanation: Got 100 on the test good luck..

Mrac [35]3 years ago
5 0

In the diagram attached inside, if electrons flow from the right half-cell to the left one through the wire, the statement that is true is that the metal strip on the right has a lower activity than the one on the left. The answer is letter A.

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What mass of HgO is required to produce 0.692 mol of O2?<br><br>2HgO(s) -&gt; 2Hg(l) + O2(g)
Vika [28.1K]

The answer for the following problem is mentioned below.

  • <u><em>Therefore 298.44 grams of mercuric oxide is needed to produce 0.692 moles of oxygen molecule </em></u>

Explanation:

Given:

no of moles of the oxygen gas = 0.692

Also given:

2 HgO  → 2 Hg + O_{2}

where,

HgO represents mercuric oxide

Hg represents mercury

O_{2} represents oxygen

To calculate:

Molar mass of HgO:

Molar mass of HgO = 216 grams

molar mass of mercury (Hg) = 200 grams

molar mass of oxygen (O) =16 grams

HgO = 200 +16 = 216 grams

We know;

       2×216 grams of HgO   →  1 mole of oxygen molecule

             ?                              →  0.692 moles of oxygen molecule

       

          = \frac{2*216*0.692}{1}

      = 298.944 grams of HgO

<u><em>Therefore 298.44 grams of mercuric oxide is needed to produce 0.692 moles of oxygen molecule </em></u>

<u />

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3 years ago
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