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Marina86 [1]
3 years ago
12

At a constant velocity, you are pulling a 10kg object with. Force P. How much work is done by P to move 87cm? Assume kinetic fri

ctional coefficient = 0.26.
Physics
1 answer:
lara [203]3 years ago
3 0
Constant velocity means............
applied force=frictional force=p=kinetic friction coefficient*mg=0.26*10*9.8=?
now we know ....  work=force*distance=0.26*10*9.8*0.87joule
plz feel free to ask if u hv any confusion!!
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4. Some early mornings , dew drops can be found on grass or a car parked outside,
horsena [70]

In some early mornings , dew drops can be found on grass or a car parked outside, but not on other materials such as the sidewalk because  the night -time temperature on grass and the car went below the dew point, but  the temperature of the concrete did not drop enough to reach the dew point  level

Dew can be formed on any object when the temperature of the object drop. When this happen, the object will be cool which will eventually cool the surrounding air around the object.

Dew drops is as a result of condensation in the air. When the cool air causes the air vapor to convert to liquid. The dew will form when the temperature of the object balances with the dew point in the surrounding environment.

In some early mornings , dew drops can be found on grass or a car parked outside, but not on other materials such as the sidewalk because  the night -time temperature on grass and the car went below the dew point, but  the temperature of the concrete did not drop enough to reach the dew point  level

Therefore the correct option is therefore A

Learn more here : brainly.com/question/13834972

3 0
3 years ago
The unit of measurement "mL" describes what property of a substance?
pychu [463]
<span>D. density is your answer</span>
8 0
3 years ago
Read 2 more answers
A city planner is working on the redesign of a hilly portion of a city. An important consideration is how steep the roads can be
Artyom0805 [142]

Explanation:

It is known that relation between force and acceleration is as follows.

                      F = m \times a

I is given that, mass is 1090 kg and acceleration is 21 m/s. Therefore, we will calculate force as follows.

              F = m \times a      

                 = 1090 \times (\frac{21}{16})

                 = 1430.625 N

Also, it is known that

      sin(\theta) = \frac{\text{Force car can exert}}{\text{Force gravity pulls car}}

      sin(\theta) = \frac{1430.625 N}{(1090 \times 9.8) N}

        \theta = 7.70 degrees

Thus, we can conclude that the maximum steepness for the car to still be able to accelerate is 7.70 degrees.

8 0
3 years ago
A crate slides down a ramp that makes a 20o angle with the ground. To keep the crate moving at a steady speed, Paige pushes back
cupoosta [38]

Answer:

-223.64684 J

Explanation:

F = Force that is applied to the crate = 68 N

s = Displacement of the crate = 3.5 m

\theta = Angle between the force and displacement vector = (180-20)

Work done is given by

W=Fscos\theta\\\Rightarrow W=68\times 3.5\times cos(180-20)\\\Rightarrow W=-223.64684\ J

The work that Paige does on the crate is -223.64684 J

6 0
3 years ago
This is the change in kinetic energy of a system in which a 16 kg object moving at 25 m/s slows to a velocity of 20 m/s
Dennis_Churaev [7]

The kinetic energy of an object is given by

KE = 0.5mv²

where m is the mass and v is the velocity.

To calculate the change in kinetic energy...

Initial KE:

KEi = 0.5mVi²

where Vi is the initial velocity.

Final KE:

KEf = 0.5mVf²

where Vf is the final velocity.

ΔKE = KEf - KEi

ΔKE = 0.5mVi² - 0.5mVf²

ΔKE = 0.5m(Vf²-Vi²)

Given values:

m = 16kg

Vi = 25m/s

Vf = 20m/s

Plug in the given values and solve for ΔKE:

ΔKE = 0.5×16×(20²-25²)

ΔKE = -1800J

5 0
3 years ago
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