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sergij07 [2.7K]
4 years ago
5

If an atom has 5 protons and 4 neutrons and is not in an excited state, how many electrons would Bohr say the atom has?

Chemistry
2 answers:
Gnom [1K]4 years ago
3 0
A it is 4 i hope it helped you

weeeeeb [17]4 years ago
3 0

the answer is A.4, hope this helps

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A chemical change always involves...
maw [93]
D- a new substance forming
4 0
3 years ago
What is a double displacement reaction?
nexus9112 [7]
<h2>Double displacement reaction:</h2>

A double displacement reaction is a type of chemical reaction where two compounds react, and positive ions (cation) and the negative ions (anion) of the two reactants switch places, forming two new compounds or products.

<h3>For example:</h3>

Na2S+2HCl→2NaCl+H2S

hope it's helpful :)

4 0
3 years ago
The volume of 0.6305 kg of a liquid is 0.430 L. What is its density in g/mL
motikmotik

Answer: 1.466 g/mL

Explanation:

\frac{0.6305 \text{kg}}{0.430 \text{L}} \cdot \frac{1000 \text{g}}{1 \text{kg}} \cdot  \frac{1 \text{L}}{1000 \text{mL}} = 1.466 \,\frac{\text{g}}{\text{mL}}

6 0
2 years ago
How many grams of Sg is required to produce 83.10 g SF6? S: +24F--&gt;8SF
ozzi

Answer : The mass of S_8 required is 18.238 grams.

Explanation : Given,

Mass of SF_6 = 83.10 g

Molar mass of SF_6 = 146 g/mole

Molar mass of S_8 = 256.52 g/mole

The balanced chemical reaction is,

S_8+24F_2\rightarrow 8SF_6

First we have to determine the moles of SF_6.

\text{Moles of }SF_6=\frac{\text{Mass of }SF_6}{\text{Molar mass of }SF_6}=\frac{83.10g}{146g/mole}=0.569moles

Now we have to determine the moles of S_8.

From the balanced chemical reaction we conclude that,

As, 8 moles of SF_6 produced from 1 mole of S_8

So, 0.569 moles of SF_6 produced from \frac{0.569}{8}=0.0711 mole of S_8

Now we have to determine the mass of S_8.

\text{Mass of }S_8=\text{Moles of }S_8\times \text{Molar mass of }S_8

\text{Mass of }S_8=(0.0711mole)\times (256.52g/mole)=18.238g

Therefore, the mass of S_8 required is 18.238 grams.

7 0
4 years ago
A compound is 2.00% H by mass, 32.7% S by mass, and 65.3% O by mass. What is its empirical formula? The second step is to calcul
Free_Kalibri [48]
Lets take 100 g of this compound,
so it is going to be 2.00 g H, 32.7 g S and 65.3 g O.

2.00 g H *1 mol H/1.01 g H ≈ 1.98 mol H
32.7 g S *1 mol S/ 32.1 g S ≈ 1.02 mol S
65.3 g O * 1 mol O/16.0 g O ≈ 4.08 mol O

1.98 mol H : 1.02 mol S : 4.08 mol O = 2 mol H : 1 mol S : 4 mol O

Empirical formula
H2SO4
8 0
3 years ago
Read 2 more answers
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