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MrRissso [65]
3 years ago
11

Of the three properties of colour, hardness, and reflectivity, which property or properties describe how a material interacts wi

th light? (1 point) SHOW EVIDENCE AND DONT POINT scam. This quiz is a Connexus academy quiz called: Physical and Chemical Properties Quick Check
reflectivity only



hardness and reflectivity only

color and reflectivity only


color, hardness, and reflectivity

Use the following observations about a material to answer the question.

The material is shiny and reflects light.
An iron nail is able to scratch the material.
Which statement best classifies the observations?

(1 point)

Only observation 1 uses a physical property of matter.


Only observation 2 uses a physical property of matter.

Neither observation uses a physical property of matter.


Both observations use a physical property of matter.
Chemistry
1 answer:
hodyreva [135]3 years ago
5 0

The properties that describe how a material interacts with light are color and reflectivity only.

Both observations use a physical property of matter.

The physical properties of substances are the properties of substances that can be observed without changing the arrangement of atoms in the substance.

The ability of an object to scratch another is known as hardness while the ability to reflect visible light is called reflectivity. Both are physical properties.

The color of a substance results from the interaction of the molecules of the substances with light. Objects have specific colors depending on the wavelength of light absorbed and subsequently emitted by the substance.

Reflectivity deals with the ability of an object to reflect visible light.

Both color and reflectivity describe how a material interacts with light.

Learn more; brainly.com/question/81085

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An object with a mass of 3.2kg has a force of 16.3 newtons to the right and 6.7 newtons to the left applied to it. What is the r
Pepsi [2]

Answer:

3m/s²

Explanation:

Given parameters:

Mass of object  = 3.2kg

Force to the right = 16.3N

Force to the left  = 6.7N

Unknown:

Acceleration of the object  = ?

Solution:

To solve this problem, we use newtons second law of motion;

   Net force  = mass x acceleration

 Net force on object  = Force to the right  - Force to the left

 Net force  = 16.3N  - 6.7N  = 9.6N

    So;

         9.6  = 3.2 x a

              a = \frac{9.6}{3.2}   = 3m/s²

7 0
3 years ago
Which factor MOST directly affects the flow of ocean currents?w of ocean currents?
Lynna [10]

B)  differences in temperature

Explanation:

The factor that most directly affects the flow of ocean currents is the differences in ocean temperature from one place to another.

Ocean current is the directional movement of the ocean water in its basin.

The main cause of ocean current is differences in temperature.

  • Ocean water on the surface receives direct sunlight.
  • This warms and the surface and decreases their density.
  • When winds blows over them, they cool and sink under their own weight.
  • The less cold water in depths rise to replace them.
  • This exchange of ocean water due to loss and gain of heat cause ocean current.

learn more:

Ocean density brainly.com/question/6760255

#learnwithBrainly

6 0
3 years ago
What functional group is aspartic acid
Westkost [7]
The functional group of aspartic acid is -COOH.
8 0
3 years ago
What is the pressure in a 245 L tank that contains 5.21 kg of helium at 27 Celsius ​
Kitty [74]
<h2><u>Answer:</u></h2>

(These are not rounded to the correct decimal)

130.94 atm

13,266.6 kPa

99,571.4 mmHg

<h2><u>Explanation:</u></h2>

<u></u>

PV = nRT

V = 245L

P = ?

R = 0.08206 (atm) , 8.314 (kPa) , 62.4 (mmHg)

T = 273.15 + 27 = 300.15K

n = 1302.5 moles

How I found (n).

5.21kg x 1000g/1kg x 1 mole/4.0g = 1302.5 moles

Now, plug all the numbers into the equation.

Pressure in atm = (1302.5)(0.08206)(300.15) / 245 = 130.94 atm (not rounded to the correct decimal)

Pressure in kPa = (1302.5)(8.314)(300.15) / 245 = 13,266.6 kPa (not rounded to the correct decimal)

Pressure in mmHg = (1302.5)(62.4)(300.15) / 245 = 99,571.4 mmHg (not rounded to the correct decimal)

5 0
3 years ago
By how much will the water temperature increases if 1046 J of heat energy are added. The specific heat of water is 4.184 J/g • °
Brilliant_brown [7]

Answer:

Option A

250 degrees Celcius

Explanation:

If 1046J of heat energy is added to water, the water will experience a rise in temperature, at a rate that is directly proportional to its specific heat capacity.

Mathematically, this can be seen as Q=C\Delta T

Where C = specific heat of water = 4.184 J/g • °C.

Q = heat energy = 1046 J

\Delta T =1046/4.148=250 degrees Celcius

Therefore, the increase in temperature that will be experienced, is for 250 degrees Celcius

8 0
3 years ago
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