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MrRissso [65]
3 years ago
11

Of the three properties of colour, hardness, and reflectivity, which property or properties describe how a material interacts wi

th light? (1 point) SHOW EVIDENCE AND DONT POINT scam. This quiz is a Connexus academy quiz called: Physical and Chemical Properties Quick Check
reflectivity only



hardness and reflectivity only

color and reflectivity only


color, hardness, and reflectivity

Use the following observations about a material to answer the question.

The material is shiny and reflects light.
An iron nail is able to scratch the material.
Which statement best classifies the observations?

(1 point)

Only observation 1 uses a physical property of matter.


Only observation 2 uses a physical property of matter.

Neither observation uses a physical property of matter.


Both observations use a physical property of matter.
Chemistry
1 answer:
hodyreva [135]3 years ago
5 0

The properties that describe how a material interacts with light are color and reflectivity only.

Both observations use a physical property of matter.

The physical properties of substances are the properties of substances that can be observed without changing the arrangement of atoms in the substance.

The ability of an object to scratch another is known as hardness while the ability to reflect visible light is called reflectivity. Both are physical properties.

The color of a substance results from the interaction of the molecules of the substances with light. Objects have specific colors depending on the wavelength of light absorbed and subsequently emitted by the substance.

Reflectivity deals with the ability of an object to reflect visible light.

Both color and reflectivity describe how a material interacts with light.

Learn more; brainly.com/question/81085

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Many oxidation-reduction reactions can be balanced by inspection. Try to balance the following reactions by inspection. In each
Phoenix [80]

Answer:

Balanced reaction: C₃H₈(g) + 5O₂(g) → 3CO₂(g) + 4H₂O(l)

Reduced: O₂

Oxidized : C₃H₈

Explanation:

For the given reaction:

C₃H₈(g) + O₂(g) → CO₂(g) + H₂O(l)

In the reactants, there are 3 C, and in the products only one, so we multiply CO₂ by 3:

C₃H₈(g) + O₂(g) → 3CO₂(g) + H₂O(l)

In the reactants, there are 8 H, and in the products, there are 2 H, so we multiply H₂O by 4:

C₃H₈(g) + O₂(g) → 3CO₂(g) + 4H₂O(l)

In the reactants are 2 O, and in the products 10 O, so we multiply O₂ by 5:

C₃H₈(g) + 5O₂(g) → 3CO₂(g) + 4H₂O(l)

The reaction is balanced.

Let's identify the oxidation number (Nox) of the elements in each compound.

C₃H₈:

H has fix Nox equal to +1, and the molecule is neutral, so, calling x the Nox of C:

3x + 8 = 0

3x = -8

x = -8/3

O₂:

Because is a pure compound, the Nox of O is 0.

CO₂:

The Nox of O is fix equal to -2, and the molecule is neutral, so, calling x the Nox of C:

2x -4 = 0

2x = 4

x = +2

H₂O:

The Nox of H and O are fixed, respectively, +1 and -2.

So, the carbon in C₃H₈ is oxidized because its Nox is increasing, and oxygen in O₂ is reduced because its Nox is decreasing.

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3 years ago
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