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3 years ago

Are all molecules of a particular substance alike?

Chemistry

1 answer:

STALIN [3.7K]3 years ago

4 0

Answer:

Yes.

Explanation:

Yes, all molecules of a particular substance are similar or alike if the substance has similar shape and structure. Molecule is made up of two or more atoms having no charge on them and the atoms present in it make bonds with each other. For example, water is made of similar molecules i. e. two hydrogen atom and one oxygen atom bonded together with a covalent bond.

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How many moles of electrons is required to deposit 5.6g of iron from a solution of iron (2) tetraoxosulphate(6)

yuradex [85]

Answer:

0.20 mol

Explanation:

Let's consider the reduction of iron from an aqueous solution of iron (II).

Fe²⁺ + 2 e⁻ ⇒ Fe

The molar mass of Fe is 55.85 g/mol. The moles corresponding to 5.6 g of Fe are:

5.6 g × 1 mol/55.85 g = 0.10 mol

2 moles of electrons are required to deposit 1 mole of Fe. The moles of electrons required to deposit 0.10 moles of Fe are

0.10 mol Fe × 2 mol e⁻/1 mol Fe = 0.20 mol e⁻

7 0

3 years ago

A 0.150-kg sample of a metal alloy is heated at 540 Celsius an then plunged into a 0.400-kg of water at 10.0 Celsius, which is c

Zarrin [17]

Answer:

$C_{alloy}=0.497\frac{J}{g\°C}$

Explanation:

Hello there!

In this case, according to this calorimetry problem on equilibrium temperature, it is possible for us to infer that the heat released by the metal allow is absorbed by the water for us to write:

$Q_{allow}=-(Q_{water}+Q_{Al})$

Thus, by writing the aforementioned in terms of mass, specific heat and temperature, we have:

$m_{alloy}C_{alloy}(T_{eq}-T_{alloy})=-(m_{water}C_{water}(T_{eq}-T_{water})+m_{Al}C_{Al}(T_{eq}-T_{Al})$

Then, we solve for specific heat of the metallic alloy to obtain:

$C_{alloy}=\frac{-(m_{water}C_{water}(T_{eq}-T_{water})+m_{Al}C_{Al}(T_{eq}-T_{Al})}{m_{alloy}(T_{eq}-T_{alloy})}$

Thereby, we plug in the given data to obtain:

$C_{alloy}=\frac{-(400g*4.184\frac{J}{g\°C} (30.5\°C-10.0\°C)+200g*0.900\frac{J}{g\°C}(30.5\°C-10.0\°C)}{150g(30.5\°C-540\°C)} \\\\C_{alloy}=0.497\frac{J}{g\°C}$

Regards!

3 0

3 years ago

A chemical test has determined the concentration of a solution of an unknown substance to be 2.41 M. a 100.0 mL volume of the so

Oksana_A [137]

Answer : The molar mass of unknown substance is, 39.7 g/mol

Explanation : Given,

Mass of unknown substance = 9.56 g

Volume of solution = 100.0 mL

Molarity = 2.41 M

Molarity : It is defined as the number of moles of solute present in one liter of volume of solution.

Formula used :

$\text{Molarity}=\frac{\text{Mass of unknown substance}\times 1000}{\text{Molar mass of unknown substance}\times \text{Volume of solution (in mL)}}$

Now put all the given values in this formula, we get:

$2.41M=\frac{9.56g\times 1000}{\text{Molar mass of unknown substance}\times 100.0mL}$

$\text{Molar mass of unknown substance}=39.7g/mol$

Therefore, the molar mass of unknown substance is, 39.7 g/mol

5 0

3 years ago

11111nata11111 [884]

Lower

Melting points of molecular solids are lower than melting points of ionic compounds

5 0

3 years ago

Read 2 more answers

The pressure that is the difference between the net hydrostatic pressure and the net colloid osmotic pressure is called

mina [271]

The pressure calculated as the difference between the net hydrostatic pressure and the net colloid osmotic pressure is known as: filtration pressure.

<h3>What is pressure?</h3>

Pressure can be defined as a measure of the force exerted per unit area of an object or body. Thus, it is usually measured in Newton per meter square.

<h3>The types of pressure.</h3>

In Science, there are different types of pressure and these include the following:

Hydrostatic pressure

Atmospheric pressure

Osmotic pressure

Filtration pressure

Filtration pressure is a pressure that is typically calculated as the difference between the net hydrostatic pressure and the net colloid osmotic pressure. Also, it promotes the filtration of fluid through a membrane.

Read more on pressure here: brainly.com/question/24827501

4 0

3 years ago