<u>Answer:</u>
<u>For a:</u> The mixture will need to produce more reactants to reach equilibrium.
<u>For b:</u> The mixture will need to produce more reactants to reach equilibrium.
<u>For c:</u> The mixture will need to produce more products to reach equilibrium.
<u>Explanation</u>:
For the given chemical equation:

The expression of
for above equation follows:
.....(1)
We are given:
Value of
= 0.26
There are 3 conditions:
- When
; the reaction is product favored. - When
; the reaction is reactant favored. - When
; the reaction is in equilibrium.
For the given options:
We are given:

Putting values in expression 1, we get:

As,
; the reaction is reactant favored
Hence, the mixture will need to produce more reactants to reach equilibrium.
We are given:

Putting values in expression 1, we get:

As,
; the reaction is reactant favored
Hence, the mixture will need to produce more reactants to reach equilibrium.
We are given:

Putting values in expression 1, we get:

As,
; the reaction is product favored.
Hence, the mixture will need to produce more products to reach equilibrium.