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3 years ago

A bottle 5.89 cm tall is 56.2 cm to the left of a plane mirror. What is the height of the image formed?

Physics

1 answer:

Hoochie [10]3 years ago

4 0

Answer:

5.89cm

..................

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This picture represents A: Reflection B: Refraction C: Interference D: Diffraction

-BARSIC- [3]

Answer:

I think it's a because it goes thru it and reflects

5 0

2 years ago

A 20 ft ladder leans against a wall. The bottom of the ladder is 3 ft from the wall at time t=0 and slides away from the wall at

stellarik [79]

Answer: 0.516 ft/s

Explanation:

Given

Length of ladder L=20 ft

The speed at which the ladder moving away is v=2 ft/s

after 1 sec, the ladder is 5 ft away from the wall

So, the other end of the ladder is at

$\Rightarrow y=\sqrt{20^2-5^2}=19.36\ ft$

Also, at any instant t

$\Rightarrow l^2=x^2+y^2$

differentiate w.r.t.

$\Rightarrow 0=2xv+2yv_y\\\\\Rightarrow v_y=-\dfrac{x}{y}\times v\\\\\Rightarrow v_y=-\dfrac{5}{19.36}\times 2=0.516\ ft/s$

5 0

3 years ago

1. How many paths through which charge can flow would be shown in a diagram of a series

Elanso [62]

1. One
2. Oohm

Hope this helps

5 0

3 years ago

A truck traveling at a velocity of 33m/s comes to a halt by decelerating at 11m/s^2. How far does the truck travel in the proces

snow_lady [41]

Answer:

The truck was moving 16.5 m/s during the time it took to stop, which was 3 seconds.

Initial velocity = 33 m/s

Final velocity = 0 m/s

Average velocity = (33 + 0) / 2 m/s = 16.5 m/s

Explanation:

First, how long does it take the truck to come to a complete stop?

( 33 m/s ) / ( 11 m / s^2 ) = 3 seconds

Then we can look at the average velocity between when the truck started decelerating and when it came to a complete stop. Because the deceleration is constant (always 11m/s^2) we can use this trick.

4 0

3 years ago

A monochromatic red laser beam emitting 1 mW at a wavelength of 638 nm is incident on a silicon solar cell. Find the following:

tia_tia [17]

Answer:

Explanation:

First we calculate the energy of the photon

E=(Planck constant × speed of light in vacuum)÷ wave length

E= $\frac{6.626*10^{34}*2.998*10^{8} }{638*10^{-9} } = 3.114*10^{49}$

Next we find the total energy per second

total energy= $1*10^{-3}W *\frac{1JS^{-1} }{1W} = 1*10^{-3} JS^{-1}$

Next we calculate the number the photon per second

= total energy ÷ energy of 1 photon

= $\frac{1*10^{-3} JS^{-1} }{3.114*10^{49} } = 3.21*10^{-53} \ photons/sec$

8 0

3 years ago