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ziro4ka [17]
3 years ago
5

Calculate the required rate of return for Climax Inc., assuming that (1) investors expect a 4.0% rate of inflation in the future

, (2) the real risk-free rate is 3.0%, (3) the market risk premium is 5.0%, (4) the firm has a beta of 2.30, and (5) its realized rate of return has averaged 15.0% over the last 5 years. Do not round your intermediate calculations.
Physics
1 answer:
Westkost [7]3 years ago
5 0

Answer:

Required rate of return = 18.5 %

Explanation:

given,                            

rate of inflection = 4 %

risk free rate = 3 %                      

market risk premium = 5 %                    

firm has a beta  = 2.30                                  

rate of return has averaged 15.0% over the last 5 years

now,                                                                      

Nominal risk free rate = risk free rate  + inflation

                                    = 3%  +  4%

                                   = 7%

Required rate of return = Nominal risk free rate + β (RPM)

                                       = 7%       +          2.3 x 5.0%

Required rate of return = 18.5 %

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Hutton, a Scottish geologist.

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3 years ago
The potential energy at x = 8 m is -2000 V and at x = 2 m is 400 V. What is the magnitude and direction of the electric field?
Stells [14]

The potential energy at x = 8 m is -2000 V and at x = 2 m is 400 V. The magnitude and direction of the electric field will be 400 V/m directed parallel to the +x-axis

Electric field, an electric property associated with each point in space when charge is present in any form. The magnitude and direction of the electric field are expressed by the value of E, called electric field strength or electric field intensity or simply the electric field.

The electric potential energy of any given charge or system of changes is termed as the total work done by an external agent in bringing the charge or the system of charges from infinity to the present configuration without undergoing any acceleration.

The relation between electric field and electric potential can be generally expressed as – “Electric field is the negative space derivative of electric potential.”

Electric field = - d V / dx

-(-2000-400) = \int\ {E} \, dx

2400 = E (8-2)

2400 V = E (6)

E = 400 V/m

To learn more about electric potential energy  here

brainly.com/question/16890427

#SPJ4

3 0
2 years ago
A certain dam generates 120 MJ of mechanical (hydroelectric) energy each minute. If the conversion from mechanical to electrical
Karolina [17]

Answer:

electric energy ( power ) = 300000 W

Explanation:

given data

mechanical (hydroelectric) energy = 120 MJ/min = 2000000 J/s

efficiency = 15 % = 0.15

solution

we know that Efficiency of electric engine is expression  as

Efficiency = Mechanical energy ÷ electric energy  ......................1

and here dam electrical power output is

put here value in equation 1

electric energy ( power ) = Efficiency × Mechanical energy ( power )

electric energy ( power ) = 0.15 × 2000000 J/s

electric energy ( power ) = 300000 W

8 0
3 years ago
I need help on this.
4vir4ik [10]
It brings cold water from the bottom of the ocean.
4 0
3 years ago
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If a ball that is 10 meters above the ground is thrown horizontally at 5.51 meters per second. a. how long will it take for the
GalinKa [24]

Answer:

a. t = 1.43 s

b. d = 7.88 m

Explanation:

a. The time of flight can be found using the following equation:

y_{f} = y_{0} + v_{0_{y}}t - \frac{1}{2}gt^{2}

Where:

y_{f}: is the final height = -10 m

y_{0}: is the initial height = 0

v_{0_{y}}: is the initial speed in the vertical direction = 0

g: is the acceleration due to gravity = 9.81 m/s²

By solving the above equation for "t" we have:

t = \sqrt{\frac{2y_{f}}{g}} = \sqrt{\frac{2*10 m}{9.81 m/s^{2}}} = 1.43 s

Hence, the ball will hit the ground in 1.43 s.

b. The distance in the horizontal direction can be found as follows:

x_{f} = x_{0} + v_{0}t + \frac{1}{2}at^{2}

Where:

x₀: is the initial position in the horizontal direction = 0

a: is the acceleration in the horizontal direction = 0 (it is moving at constant speed)

x_{f} = 5.51 m/s*1.43 s = 7.88 m

Therefore, the ball will travel 7.88 m before it hits the ground.

I hope it helps you!

4 0
3 years ago
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