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Schach [20]
3 years ago
9

I need help!! i’ll give 20 points

Physics
1 answer:
larisa86 [58]3 years ago
8 0

Answer:

780 m to travel north

Explanation:

6 m over = 750

53 degree so it will take about 2 min to reach the destination

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Help me please I can't get the final step​
inna [77]

Answer:

\displaystyle m=\frac{2}{3},\ n=\frac{4}{3}

Explanation:

<u>Dimensional Analysis</u>

It's given the relation between quantities A, B, and C as follows:

\displaystyle A=\frac{3}{2}B^mC^n

and the dimensions of each variable is:

A=L^2T^2

B=LT^{-1}

C=LT^2

Substituting the dimensions into the relation (the coefficient is not important in dimension analysis):

\displaystyle L^2T^2=\left(LT^{-1}\right)^m\left(LT^2\right)^n

Operating:

L^2T^2=\left(L^mT^{-m}\right)\left(L^nT^{2n}\right)

L^2T^2=L^{m+m}T^{-m+2n}

Equating the exponents:

m+n=2

-m+2n=2

Adding both equations:

3n=4

Solving:

n=4/3

m=2-4/3=2/3

Answer:

\mathbf{\displaystyle m=\frac{2}{3},\ n=\frac{4}{3}}

6 0
2 years ago
Which lens is shown in the diagram?
mojhsa [17]

Where's the diagram?

5 0
2 years ago
Read 2 more answers
A cave explorer travels 3.00 m eastward, then 6.50 m northward, and finally 12.0 m westward. Find the magnitude of the net displ
mina [271]
<span>3 meters east and 15 meters west evens out to 12 meters west. the answer is 12 meters west
</span>
7 0
3 years ago
A uniform steel girder of weight 22KN and of length 12m is lifted off the ground at one end by means of a crane. When the raised
Keith_Richards [23]

Answer:

Explanation:

For free body diagram see attached sheet .

W is weight of steel girder acting at the middle point of its length . T is tension in the cable .

OB = √ ( 12² - 2² )

= 11.83 m .

OC = 11.83 / 2 = 5.915 m

Taking moment of tension T and weight W about point O

W x OC = T x OB

22 x 5.915 = T x 11.83

T = 22 x 5.915 / 11.83

= 11 kN

Considering forces acting in vertical direction and equating forces in opposite direction

T + R = W

R = W - T

= 22 - 11 = 11 KN

So force of grinder on the ground = R

= 11 KN.

8 0
2 years ago
Dale and Alex push on opposite sides of a couch. Dale pushes to the left with a force of 250 N, while Alex pushes to the right w
bonufazy [111]
F=ma
a=F/m

F=+250N + (-130N)=120N LEFT
('m summing my forces because they are moving about the same axis, and the negative/positive accounts for the arbitrary directions I assign)
m=32kg

F=120N/32kg=3.75m/s^2 to the LEFT

3.75m/s^2 to the LEFT
3 0
3 years ago
Read 2 more answers
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