Hello from MrBillDoesMath!
Answer:
b2 = 5
Discussion:
A = 1/2 h (b1 + b2)
.
Substituting A = 16, h = 4, and b1=3 in the above formula gives:
16 = (1/2) (4)( 3 + b2) => (as (1/2)4 = 2) )
16 = 2 ( 3 + b2) => (divide both sides by 2)
8 = (3 + b2) => (subtract 3 from both sides)
8-3 = b2 =>
5 = b2
Check Area formula:
Does A = 16 = (1/2)(4)(3+5) ?
Does 16 = (1/2) (4)(8) ?
Does 16 = (1/2)(32) ? Yes it does so our calculation for b2 is correct
Thank you,
MrB
Answer:
Not true.
Step-by-step explanation:
Whole numbers are integers that are 0 or greater than 0. Since 0 is a whole number and x > 0 does not include 0, the statement is not true. Only the sign ≥ includes 0.
The vertex is (3,0).
The 3 inside the abs val bar tells you the x value of the vertex is 3. No number outside the abs value bar is a +0 which is the y value of the vertex.
Answer:
A
Step-by-step explanation:
Answer:
Step-by-step explanation:
Left
As near as I can tell, the question is x^(1/2) * x^(1/2) = The bases are the same, so all you do is add the powers.
x^(1/2 + 1/2) = x^1 which is just x.
Right
The is another one where the work is hard to show. The numerator (m) of the fraction is the power and the denominator (n) is the root. That sentence is all the work there is.
So you would write ![\sqrt[m]{x^{n} } = x^{\frac{m}{n} }](https://tex.z-dn.net/?f=%5Csqrt%5Bm%5D%7Bx%5E%7Bn%7D%20%7D%20%3D%20x%5E%7B%5Cfrac%7Bm%7D%7Bn%7D%20%7D)
