All categories

3 years ago

Calculate the mass of chromium produced from 50g of Cr2O3.

Chemistry

1 answer:

Klio2033 [76]3 years ago

8 0

Answer: 34 gram of chromium produced from 50g of $Cr_2O_3$

Explanation:

To calculate the moles :

$\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}$

$\text{Moles of} Cr_2O_3=\frac{50g}{152g/mol}=0.33moles$

The decomposition of $Cr_2O_3$ follows the equation :

$2Cr_2O_3\rightarrow 4Cr+3O_2$

According to stoichiometry :

2 moles of $Cr_2O_3$ produce = 4 moles of $Cr$

Thus 0.33 moles of $Cr_2O_3$ will produce= $\frac{4}{2}\times 0.33=0.66moles$ of $Cr$

Mass of $Cr=moles\times {\text {Molar mass}}=0.66moles\times 52g/mol=34g$

Thus 34 gram of chromium produced from 50g of $Cr_2O_3$

You might be interested in

Name a metal and non metal which are liquid at normal pressure and temperature

liraira [26]

Answer:

metal : Mercury(Hg)

non metal : bromine (Br)

Explanation:

mercury is liquid at room temperature and pressure and the same as bromine

6 0

2 years ago

Which of the following correctly represents the transmutation in which a curium-242 nucleus is bombarded with an alpha particle

Alekssandra [29.7K]

Answer: The chemical equation is written below.

Explanation:

Transmutation is defined as the process in which one chemical isotope gets converted to another chemical isotope. The number of protons or neutrons in the isotope gets changed.

The chemical equation for the reaction of curium-242 nucleus with alpha particle (helium nucleus) follows:

$_{96}^{242}\textrm{Cm}+_4^2\textrm{He}\rightarrow _{98}^{245}\textrm{Cf}+_0^1\textrm{n}$

The product formed in the nuclear reaction are californium-245 nucleus and a neutron particle.

6 0

3 years ago

Consider the reaction. 2 Pb ( s ) + O 2 ( g ) ⟶ 2 PbO ( s ) An excess of oxygen reacts with 451.4 g of lead, forming 367.5 g of

Art [367]

Answer : The percent yield of the reaction is, 75.6 %

Solution : Given,

Mass of Pb = 451.4 g

Molar mass of Pb = 207 g/mole

Molar mass of PbO = 223 g/mole

First we have to calculate the moles of Pb.

$\text{ Moles of }Pb=\frac{\text{ Mass of }Pb}{\text{ Molar mass of }Pb}=\frac{451.4g}{207g/mole}=2.18moles$

Now we have to calculate the moles of $PbO$

The balanced chemical reaction is,

$2Pb(s)+O_2(g)\rightarrow 2PbO(s)$

From the reaction, we conclude that

As, 2 mole of $Pb$ react to give 2 mole of $PbO$

So, 2.18 mole of $Pb$ react to give 2.18 mole of $PbO$

Now we have to calculate the mass of $PbO$

$\text{ Mass of }PbO=\text{ Moles of }PbO\times \text{ Molar mass of }PbO$

$\text{ Mass of }PbO=(2.18moles)\times (223g/mole)=486.1g$

Theoretical yield of $PbO$ = 486.1 g

Experimental yield of $PbO$ = 367.5 g

Now we have to calculate the percent yield of the reaction.

$\% \text{ yield of the reaction}=\frac{\text{ Experimental yield of }PbO}{\text{ Theoretical yield of }PbO}\times 100$

$\% \text{ yield of the reaction}=\frac{367.5g}{486.1g}\times 100=75.6\%$

Therefore, the percent yield of the reaction is, 75.6 %

3 0

3 years ago

Electron configurations are a shorthand form of an orbital diagram, describing which orbitals are occupied for a given element.

kipiarov [429]

Answer:

[Ar] 3d10 4s2 4p3 is shorthand, 1s22s22p63s23p63d104s24p3 long hang

Explanation:

The shorthand is made using the lowest & closest noble gas, and picking up where it leaves off as follows, and longhand is made from a followed pattern you can easily find

3 0

3 years ago

Read 2 more answers

What percentage of the filtrate's water that enters bowman's capsule is reabsorbed into the blood? select one:

maksim [4K]

99% of the filtrate's water that enter bowman's capsule is reabsorbed into the blood. This is because the water and the salts contained in the filtrate are needed for optimal functioning of the body system.

3 0

3 years ago