The energy required to break one mole of Cl - Cl bond is 242 kJ/mol
Answer:
bond angles of 120 degrees.
The energy that is
essential to break one C-H bond is 414 kJ/mol. Since, there are four C-H bonds
in CH4, the energy Δ HCH4 for
breaking all the bonds is calculated as Δ HCH4 = 4 x bond energy of C-H bond. By
multiplying the 4 with the 414 kJ/mol you can get the answer of 1656 kJ/mol CH4
molecules.
First we have to find Ka1 and Ka2
pKa1 = - log Ka1 so Ka1 = 0.059
pKa2 = - log Ka2 so Ka2 = 6.46 x 10⁻⁵
Looking at the values of equilibrium constants we can see that the first one is really big compared to second one. so, the pH will be affected mainly by the first ionization of the acid.
Oxalic acid is H₂C₂O₄
H₂C₂O₄ ⇄ H⁺ + HC₂O₄⁻
0.0356 M 0 0
0.0356 - x x x
Ka1 =
![\frac{[H^+][HC2O4^-]}{[H2C2O4]}](https://tex.z-dn.net/?f=%20%5Cfrac%7B%5BH%5E%2B%5D%5BHC2O4%5E-%5D%7D%7B%5BH2C2O4%5D%7D%20)
= x² / 0.0356 - x
x = 0.025 M
pH = - log [H⁺] = - log (0.025) = 1.6