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3 years ago

14

Three positive charges are arranged as shown in the diagram.

2 answers:

Firlakuza [10]3 years ago

6 0

magnitude: 1.75 N

direction: 6.2° north of east

navik [9.2K]3 years ago

4 0

The Richter Scale is not commonly used anymore, except for small earthquakesrecorded locally, for which ML and Mblg are the only magnitudes that can be measured. For all other earthquakes, the moment magnitude scale is a more accurate measure of the earthquake size.

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For a spacecraft or a molecule to leave the moon, it must reach the escape velocity (speed) of the moon, which is 2.37 km/s. The

guapka [62]

Answer:

Vrms = 291 m/s

Explanation:

The root mean square velocity or vrms is the square root of the average square velocity and is. vrms=√3RTM. Where M is equal to the molar mass of the molecule in kg/mol.

Temperature = 365 K

Root mean square velocity = ?

molar mass of oxygen = 16 g/mol.

But xygen gas (O2) is comprised of two oxygen atoms bonded together. Therefore:

molar mass of O2 = 2 x 16

molar mass of O2 = 32 g/mol

Convert this to kg/mol:

molar mass of O2 = 32 g/mol x 1 kg/1000 g

molar mass of O2 = 3.2 x 10-2 kg/mol

Molar mass of Oxygen = 3.2 x 10-2 kg/mol

Vrms = √[3(8.3145 (kg·m2/sec2)/K·mol)(365 K)/3.2 x 10-2 kg/mol]

Vrms = 291 m/s

8 0

3 years ago

Read 2 more answers

what will be the acceleration due to gravity at up planet whose mass is 8 times the mass of the earth and whose radius is twice

Alexxandr [17]

Hope it cleared your doubt.

3 0

3 years ago

Ships A and B leave port together. For the next two hours, ship A travels at 40.0 mph in a direction 35.0° west of north while t

kompoz [17]

Answer:

Explanation:

Given

Ship A velocity is 40 mph and is traveling 35 west of north

Therefore in 2 hours it will travel $40\times 2=80 miles$

thus its position vector after two hours is

$r_A=-80sin35\hat{i}+80cos35\hat{j}$

similarly B travels with 20 mph and in 2 hours

$=20\times 2=40 miles Its position vector[tex]r_B=40sin80\hat{i}+40cos80\hat{j}$

Thus distance between A and B is

$r_{AB}=\left ( -40sin80-80sin35\right )\hat{i}+\left ( 80cos35-40cos80\right )\hat{j}$

$|r_{AB}|=\sqrt{\left ( -40sin80-80sin35\right )^2+\left ( 80cos35-40cos80\right )^2}$

$|r_{AB}|=103.45 miles$

Velocity of A

$v_A=-40sin35\hat{i}+40cos35\hat{j}$

Velocity of B

$v_B=20sin80\hat{i}+20cos80\hat{j}$

Velocity of A w.r.t B

$v_{AB}=v_A-v_B$

$v_{AB}=\left ( -20sin80-40sin35\right )\hat{i}+\left ( 40cos35-20cos80\right )\hat{j}$

4 0

3 years ago

Name of compounds<br>a. H2Co3<br>b. NH4OH<br>c.AlPO4<br>d.NaOH<br>e.AuCI3<br>

seraphim [82]

Answer:

<em><u>a) </u></em><em><u> </u></em><em><u>Carbonic acid</u></em>

<em><u>b</u></em><em><u>)</u></em><em><u> </u></em><em><u>ammonium hydroxide</u></em>

<em><u>c</u></em><em><u>)</u></em><em><u> </u></em><em><u>Aluminum phosphate</u></em>

<em><u>d</u></em><em><u>)</u></em><em><u> </u></em><em><u>Sodium hydroxide</u></em>

<em><u>e</u></em><em><u>)</u></em><em><u> </u></em><em><u>Gold trichloride</u></em>

Explanation:

<em>I</em><em> </em><em>hope this</em><em> </em><em>will help</em><em> </em><em>you</em><em> </em><em>buddy</em><em> </em>

3 0

3 years ago

A graph can be described as:

pantera1 [17]

D all of the above

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6 0

2 years ago