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maksim [4K]
4 years ago
14

Three positive charges are arranged as shown in the diagram.

Physics
2 answers:
Firlakuza [10]4 years ago
6 0

magnitude: 1.75 N

direction: 6.2° north of east

navik [9.2K]4 years ago
4 0

The Richter Scale is not commonly used anymore, except for small earthquakesrecorded locally, for which ML and Mblg are the only magnitudes that can be measured. For all other earthquakes, the moment magnitude scale is a more accurate measure of the earthquake size.

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Describe the motion of an object that has an elephant acceleration of 0 mi./s squared
Scorpion4ik [409]
The object does not move.
8 0
3 years ago
Suppose a radio signal (light) travels from Earth and through space at a speed of 3 × 108/ (this is the speed of light in vacuum
Umnica [9.8K]

Answer:

18*10^10 meters

Explanation:

V= d/t         10 mins = 600 seconds

3*10^8 = d/600s

(3*10^8)*(6*10^2) = d

d = 18*10^10 m

6 0
4 years ago
A parallel plate capacitor is constructed with a dielectric slab with κ = 1.5 inserted between the plates. The area of each plat
maksim [4K]

Answer:

The value is V =  4.533  \  V

Explanation:

From the question we are told that

The dielectric constant is k = 1.5

The area of each plate is A =  5 \ cm^2 = 0.0005 m^2

The distance between the plates is d= 1 \  mm  =  0.001 \  m

The charge on the capacitor is Q =  6*10^{-11} \  C

Generally the electric field in a vacuum is mathematically represented as

E_o  =  \frac{V_o}{d}

Generally V_o is the voltage of the capacitor which is mathematically represented as

V_o =  \frac{Q}{C_o}

Here C_o is the capacitance of the capacitor in a vacuum which is mathematically represented as

C_o =  \frac{\epsilon_o * A}{d}

Here epsilon_o is a constant with value epsilon_o= 8.85*10^{-12} C^2 \cdot N^{-1} \cdot m^{-2}

=> C_o =  \frac{8.85*10^{-12} * 0.0005 }{0.001}

=> C_o =  4.425 *10^{-12}  \  F

So

V_o =  \frac{6*10^{-11} }{  4.425 *10^{-12}}

V_o =  13.6 \  V

So

E_o  =  \frac{ 13.6}{0.001}

=> E_o  = 13600 \ V/m

The electric field when the dielectric slab is inserted is mathematically represented as

E =  \frac{E_o}{k}

=> E =  \frac{13600}{1.5}

=> E =9067  \ V/m

Generally the electric field between the plates is mathematically evaluated as

E_{N} =  E_o - E

=> E_{N} =  13600- 9067

=> E_{N} = 4533 \  V/m

Generally the potential difference between the plates is

V =  4533   *  0.001

=> V =  4.533  \  V

6 0
4 years ago
The star Betelgeuse is 6.1 x 10^18 m away from Earth. How old is the light we see from that star when it reaches us? There are 3
castortr0y [4]

Answer:

635 years old

Explanation:

The light reaching the earth from the sun will travel at a speed called the speed of light, and this has a universal value of 3 × 10⁸ m/s. Bearing this in mind, let us calculate the age of the light reaching the Earth from the sun:

Distance of star from Earth = 6.1 × 10⁸m

Speed of light = 3 × 10⁸ m/s

We have distance and speed, let us calculate the time of travel of the light from the star to the earth.

Distance = speed × time

6.1 × 10⁸ = 3 × 10⁸ × time

time = \frac{6.1 \times 10^{18}}{3 \times 10^8}

In order to do the division above, we will divide the whole numbers normally, then we will apply the law of indices to the power that says:

Xᵃ ÷ Xᵇ = X⁽ᵃ⁻ᵇ⁾

\therefore time = \frac{6.1 \times 10^{18}}{3 \times 10^8}\\= \frac{2.03 \times 10^{(18-8)}}{1} \\= 2.03 \times 10^{10}}\ seconds

Next, we are told that there are 3.2 × 10⁷ seconds in a year.

∴ The number of years travelled by the light from the star:

3.2\ \times 10^7\ seconds = 1\ year\\1\ second =  \frac{1}{3.2\ \times 10^7} \\\therefore 2.03 \times 10^{10}\ seconds = \frac{2.03 \times 10^{10}}{3.2\ \times 10^7}

please note that:

2.03 × 10¹⁰ = 20300000000

3.2 × 10⁷ = 32000000

\therefore \frac{2.03 \times 10^{10}}{3.2\ \times 10^7}\\= \frac{20300000000}{32000000} \\\\= \frac{20300}{32} \\= 634.347\ years\\

The closest answer in the option is 635 years, and we are short of this by some points due probably to approximations in the calculation.

8 0
3 years ago
in 10 minutes a heart can beat 700 times at this rate in how many minutes will a heart beat 140 times at what rate can a heart b
Andru [333]
Answer: Heart can beat 140 times in = 2 minutes
3 0
3 years ago
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