the social dilemma and coded bias documentary compare and contrast (goods and bad) they may have on future technology developmen
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Answer:
component of acceleration are a = 3.37 m/s² and ar = 22.74 m/s²
magnitude of acceleration is 22.98 m/s²
Explanation:
given data
velocity = 10 m/s
initial time to = 0
distance s = 400 m
time t = 14 s
to find out
components and magnitude of acceleration after the car has travelled 200 m
solution
first we find the radius of circular track that is
we know distance S = 2πR
400 = 2πR
R = 63.66 m
and tangential acceleration is
S = ut + 0.5 ×at²
here u is initial speed and t is time and S is distance
400 = 10 × 14 + 0.5 ×a (14)²
a = 3.37 m/s²
and here tangential acceleration is constant
so velocity at distance 200 m
v² - u² = 2 a S
v² = 10² + 2 ( 3.37) 200
v = 38.05 m/s
so radial acceleration at distance 200 m
ar =
ar =
ar = 22.74 m/s²
so magnitude of total acceleration is
A =
A =
A = 22.98 m/s²
so magnitude of acceleration is 22.98 m/s²
Answer:
Logarithmic decrement is equal to 0.182
Explanation:
given,
amplitude decay = 9 dB
number of cycles = 12 cycles
mass of the system = 7 kg
spring stiffness = 3000 N/m
logarithmic decrement = ?
now,
logarithmic decreament =
=
=ln (1.2)
= 0.182
Hence, Logarithmic decrement is equal to 0.182