Ask question

Ask question

All categories

3 years ago

5

Change the following percentage to fraction

"TexFormula1" title="116 \ \frac{2}{3} \%" alt="116 \ \frac{2}{3} \%" align="absmiddle" class="latex-formula">

1 answer:

marta [7]3 years ago

3 0

I think the answer is 350/3

You might be interested in

HELP DUE IN 20 MINS! Leave answers as simplified fractions if necessary.<br><br> m =??

mezya [45]

The answer is M = -24

3 0

3 years ago

Read 2 more answers

Please help be fast I’m on a test

Leto [7]

Hundreds because the answer is 251 so the 2 is in the hundreds

8 0

3 years ago

Write the equation

Sedaia [141]

Answer:

ask google

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

5(a−b), if a=−4; b=−2

Helen [10]

Step-by-step explanation:

Putting values of a and b

5 ( - 4 - (-2))

5 ( - 4 + 2)

5 ( - 2)

= - 10

4 0

3 years ago

If (3-4i) (x+yi) = 1 + 0i. The value of x and y is

Black_prince [1.1K]

Step-by-step explanation:

$\textsf{\large{\underline{Solution}:}}$

<h3><u>Given That:</u></h3>

$\rm: \longmapsto (3 - 4i)(x + iy) = 1 + 0i$

$\rm: \longmapsto 3(x + iy) - 4i(x + iy)= 1 + 0i$

$\rm: \longmapsto 3x + 3iy - 4ix +4y= 1 + 0i$

<u>On rearranging the terms, we get:</u>

$\rm: \longmapsto (3x + 4y)+ (3y - 4x)i = 1 + 0i$

<u>Comparing both sides, we get:</u>

$\rm: \longmapsto 3x + 4y = 1 --- (i)$

$\rm: \longmapsto 3y - 4x = 0 --- (ii)$

<u>Multiplying (i) by 4, we get:</u>

$\rm: \longmapsto 12x + 16y = 4--- (iii)$

<u>Multiplying (ii) by 3, we get:</u>

$\rm: \longmapsto 9y - 12x = 0 --- (iv)$

<u>Adding equations (iii) and (iv), we get:</u>

$\rm: \longmapsto25y = 4$

$\rm: \longmapsto y =\dfrac{4}{25}$

<u>From (ii), we get:</u>

$\rm: \longmapsto 3y - 4x = 0$

$\rm: \longmapsto 3y = 4x$

$\rm: \longmapsto x = \dfrac{3}{4} y$

$\rm: \longmapsto x = \dfrac{3}{4} \times \dfrac{4}{25}$

$\rm: \longmapsto x = \dfrac{3}{25}$

<u>Therefore:</u>

$\rm: \longmapsto (x,y)= \bigg( \dfrac{3}{25}, \dfrac{4}{25} \bigg)$

★ <u>Which is our required answer.</u>

$\textsf{\large{\underline{More To Know}:}}$

$\rm1.\ i^{4n} = 1$

$\rm2. \ i^{4n+1} = i$

$\rm3.\ i^{4n+2} = -1$

$\rm4.\ i^{4n+3} = -i$

4 0

3 years ago