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crimeas [40]
3 years ago
15

Which hybridization of orbitals is present in beryllium fluoride, BeF2?

Chemistry
1 answer:
alisha [4.7K]3 years ago
4 0

Answer is: beryllium fluoride has sp hybridization.

Beryllium (Be) is metal from group 2 and fluorine (F) is nonmetal from group 17.

Electron configuration of beryllium atom: ₄Be: 1s² 2s².

Electron configuration of fluorine atom: ₉F 1s² 2s² 2p⁵.

In beryllium, one electron from 2s orbital gets excitted to the level of 2p orbital; s and p orbital are hybridized and form two sp-hybridised  orbitals arranged in a linear shape.

Two fluorine atoms come closer to beryllium atom and sp hybridised orbitals of Be and p orbital of F get overlapped with each other and make bonds.

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Determine the [h3o+] of a 0.210 m solution of formic acid.
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When the Pka for formic acid = 3.77
and Pka = -㏒ Ka 
   3.77 = -㏒ Ka
∴Ka = 1.7x10^-4 

when Ka = [H+][HCOO-}/[HCOOH]

when we have Ka = 1.7x10^-4 &[HCOOH] = 0.21 m
so by substitution: by using ICE table value
1.7x10^-4 = X*X / (0.21-X)
(1.7x10^-4)*(0.21-X) = X^2      by solving this equation for X

∴X = 0.0059
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∴PH= -㏒ [H+]
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3 years ago
Negative radical in the periodic table​
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3 years ago
Describe Rutherford's contribution to the atomic model.
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3 years ago
How many moles of solute are in 53.1 mL of 12.5M HCI?
Deffense [45]
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From this relation, we can figure out the number of moles of solute by multiplying the molarity of the solution by the volume in liters.

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2 years ago
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