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crimeas [40]
3 years ago
15

Which hybridization of orbitals is present in beryllium fluoride, BeF2?

Chemistry
1 answer:
alisha [4.7K]3 years ago
4 0

Answer is: beryllium fluoride has sp hybridization.

Beryllium (Be) is metal from group 2 and fluorine (F) is nonmetal from group 17.

Electron configuration of beryllium atom: ₄Be: 1s² 2s².

Electron configuration of fluorine atom: ₉F 1s² 2s² 2p⁵.

In beryllium, one electron from 2s orbital gets excitted to the level of 2p orbital; s and p orbital are hybridized and form two sp-hybridised  orbitals arranged in a linear shape.

Two fluorine atoms come closer to beryllium atom and sp hybridised orbitals of Be and p orbital of F get overlapped with each other and make bonds.

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It has  chiral center.

Here , the chiral carbon is attached to the 4 distinct groups such as :  methyl , ethyl , bromine , bromomethane .

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Di-symmetry is that which have no center of symmetry and plane of symmetry and alternate axis of symmetry .

<h3>Chiral center :</h3>

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<h3>What is optical isomerism ?</h3>

Same molecular formula and same structural formula . also have same physical and chemical properties .

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brainly.com/question/9522537

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