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crimeas [40]
3 years ago
15

Which hybridization of orbitals is present in beryllium fluoride, BeF2?

Chemistry
1 answer:
alisha [4.7K]3 years ago
4 0

Answer is: beryllium fluoride has sp hybridization.

Beryllium (Be) is metal from group 2 and fluorine (F) is nonmetal from group 17.

Electron configuration of beryllium atom: ₄Be: 1s² 2s².

Electron configuration of fluorine atom: ₉F 1s² 2s² 2p⁵.

In beryllium, one electron from 2s orbital gets excitted to the level of 2p orbital; s and p orbital are hybridized and form two sp-hybridised  orbitals arranged in a linear shape.

Two fluorine atoms come closer to beryllium atom and sp hybridised orbitals of Be and p orbital of F get overlapped with each other and make bonds.

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Molecular formula is the chemical formula which depicts the actual number of atoms of each element present in the compound.  

Empirical formula is the simplest chemical formula which depicts the whole number of atoms of each element present in the compound.

1. Al_2Br_6 has empirical formula of AlBr_3

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