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max2010maxim [7]
2 years ago
7

If a bus travels 6 km in 10 minutes, what distance does it travel in 1 second ​

Physics
2 answers:
loris [4]2 years ago
4 0

Answer:

Your answer is 10 m/s...

Masteriza [31]2 years ago
4 0

Answer:

I think it is 1 foot???

Explanation:

sorry if this is not what u are looking for..

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Time Intervals in Ice Ages
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It started off with 68% less than it did at the peak, and later created a void and melted the remainder of the ice at about 92%
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Compare and contrast the particle motion in each state of matter
Vladimir79 [104]

Answer:

Gases, liquids and solids are all made up of microscopic particles, but the behaviors of these particles differ in the three phases. ... gas are well separated with no regular arrangement. liquid are close together with no regular arrangement. solid are tightly packed, usually in a regular pattern.

<h3>Hope this is fine for you</h3>
6 0
3 years ago
Magnetic field lines are more concentrated at the poles of the magnet<br> True<br> False
yKpoI14uk [10]

Answer:

True! UwU

Explanation:

the magnetic field is strongest near to the poles of the magnet were the lines of flux are more closely spaced.

8 0
3 years ago
Explain the law of conservation of energy in your own words .
melamori03 [73]
The law of conservation of energy states that in any reaction, energy cannot be created or destroyed.

In other words, energy has to be conserved in every reaction.
4 0
3 years ago
A thin, uniform rod is bent into a square of side length a. If the total mass is M, find the moment of inertia about an axis thr
Papessa [141]

Answer:

The  moment of inertia about an axis through the center and perpendicular to the plane of the square is

    I_s =  \frac{Ma^2}{3}

Explanation:

From the question we are told that

   The length of one side of the square is  a

   The total mass of the square is  M

Generally the mass of one size of the square is mathematically evaluated as

    m_1 = \frac{M}{4}

Generally the moment of inertia of one side of the square is mathematically represented as

        I_g =  \frac{1}{12}  *  m_1 * a^2

Generally given that m_1 = m_2 = m_3 = m_4 = m it means that this moment inertia evaluated above apply to every side of the square  

Now substituting for  m_1

  So

       I _g=  \frac{1}{12}  *  \frac{M}{4} * a^2

Now according to  parallel-axis theorem the moment of inertia of one side of the square about an axis through the center and perpendicular to the plane of the square is mathematically represented as

      I_a =  I_g + m [\frac{q}{2} ]^2

=>    I_a =  I_g + {\frac{M}{4} }* [\frac{q}{2} ]^2

substituting for I_g

=>    I_a =  \frac{1}{12}  *  \frac{M}{4} * a^2 + {\frac{M}{4} }* [\frac{q}{2} ]^2

=>    I_a = \frac{Ma^2}{48} + \frac{Ma^2}{16}

=>    I_a = \frac{Ma^2}{12}

Generally the moment of inertia of the square about an axis through the center and perpendicular to the plane of the square is mathematically represented as

      I_s = 4 * I_a

=>   I_s = 4 * \frac{Ma^2}{12}

=>   I_s =  \frac{Ma^2}{3}

8 0
3 years ago
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