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Sergeu [11.5K]
2 years ago
5

Two identical dump trucks are at a work site. One is returning with a full load, and the other is empty. Both are traveling at 3

5 mph. Which has more kinetic energy?
Chemistry
1 answer:
elena55 [62]2 years ago
8 0

Answer:

The one with the full load.

Explanation: We can prove this by doing V^2 X M = KE

where V= velocity M= mass and KE= kinetic energy.

is both are traveling at the same speed (let's say 2kmph) and one has a mass of 50 kg with the other having a mass of 100kg.

(plug in the values) .   2^2 X 50 = KE and 2^2 X 100= KE

(simplify) 200=KE and 400=KE

This proves that a dump truck with a larger load (if traveling at the same speed) will always contain more energy than a dump truck with a smaller load.

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Do protons determine isotopes
Bezzdna [24]

Answer:

No

Explanation:

Protons determine the type of element it is which the number of protons.

Isotopes are determined by the same elements with the same amount of protons, but different number of neutrons.

5 0
3 years ago
The enthalpy change for converting 1.00 mol of ice at -50.0 ∘c to water at 60.0∘c is ________ kj. the specific heats of ice, wat
guajiro [1.7K]
First, we have to get:

1- The heat required to increase T of ice from -50 to 0 °C:

according to q formula:

q1 = m*C*ΔT

when m is the mass of ice = mol * molar mass

                                             =  1 mol * 18 mol/g

                                            = 18 g

and C is the specific heat capacity of ice = 2.09 J/g-K

and ΔT change in temperature = 0- (-50) = 50°C

by substitution:

∴q1 = 18 g * 2.09 J/g-K *50°C

       = 1881 J = 1.881 KJ

2- the heat required to melt this mass of ice is :

q2 = n*ΔHfus 

when n is the number of moles of ice = 1 mol

and ΔHfus = 6.01 KJ/mol

by substitution:

q2 = 1 mol * 6.01 KJ/mol

     = 6.01 KJ

3- the heat required to increase the water temperature from 0°C to 60 °C is:

q3 = m*C*ΔT

when m is the mass of water = 18 g 

C is the specific heat capacity of water = 4.18 J/g-K

ΔT is the change of Temperature of water = 60°C - 0°C = 60°C

by substitution:

∴q3 = 18 g * 4.18 J/g-K * 60°C

      = 4514 J = 4.514 KJ

∴the total change of enthalpy = q1+q2+q3

                                                  = 1.881 KJ  +6.01 KJ + 4.514 KJ

                                                  = 12.405 KJ


5 0
3 years ago
The volume of a sample gas, initially at 25 C and 158 mL, increased to 450 mL. What is the final temperature of the sample of ga
Rashid [163]

Answer:

Final temperature of the gas is  576 ^{0}\textrm{C}.

Explanation:

As the amount of gas and pressure of the gas remains constant therefore in accordance with Charles's law:

                                       \frac{V_{1}}{T_{1}}=\frac{V_{2}}{T_{2}}

where V_{1} and V_{2} are volume of gas at T_{1} and T_{2} temperature (in kelvin scale) respectively.

Here V_{1}=158mL , T_{1}=(273+25)K=298K and V_{2}=450mL

So  T_{2}=\frac{V_{2}T_{1}}{V_{1}}=\frac{(450mL)\times (298K)}{(158mL)}=849K 

849 K = (849-273) ^{0}\textrm{C} = 576 ^{0}\textrm{C}

So final temperature of the gas is  576 ^{0}\textrm{C}.

3 0
3 years ago
Binary ionic compound of calcium and oxygen
Vlad1618 [11]
Socratic helps for you page
7 0
2 years ago
Which two phase changes occur when you increase the heat?
muminat

Answer:

Heat going into a substance changes it from a solid to a liquid or a liquid to a gas. Removing heat from a substance changes a gas to a liquid or a liquid to a solid.

Liquid → Gas: 

VaporizationGas → Liquid:

 CondensationSolid → Liquid:

 Melting or fusion

Solid → Gas: Sublimation

Explanation:

8 0
1 year ago
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