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Crank
3 years ago
12

The water-gas shift reaction CO(g)+H2O(g)⇌CO2(g)+H2(g) is used industrially to produce hydrogen. The reaction enthalpy is ΔH∘=−4

1kJ.Part ATo increase the equilibrium yield of hydrogen would you use high or low temperature?Drag the terms on the left to the appropriate blanks on the right to complete the sentenceshighexothermiclowendothermicdecreasingincreasingWe would use We would use blanktemperature. For an blankreaction such as this, blanktemperature increases the value of Kand the amount of products at equilibrium. temperature. For an We would use blanktemperature. For an blankreaction such as this, blanktemperature increases the value of Kand the amount of products at equilibrium. reaction such as this, We would use blanktemperature. For an blankreaction such as this, blanktemperature increases the value of Kand the amount of products at equilibrium. temperature increases the value of K and the amount of products at equilibrium.
Chemistry
1 answer:
denis23 [38]3 years ago
3 0

Answer:

To increase the yield of H₂ we would use a low temperature.

For an exothermic reaction such as this, decreasing temperature increases the value of K and the amount of products at equilibrium. Low temperature increases the value of K and the amount of products at equilibrium.

Explanation:

Let´s consider the following reaction:

CO(g) + H₂O(g) ⇌ CO₂(g) + H₂(g)

When a system at equilibrium is disturbed, the response of the system is explained by Le Chatelier's Principle: <em>If a system at equilibrium suffers a perturbation (in temperature, pressure, concentration), the system will shift its equilibrium position to counteract such perturbation</em>.

In this case, we have an exothermic reaction (ΔH° < 0). We can imagine heat as one of the products. If we decrease the temperature, the system will try to raise it favoring the forward reaction to release heat and, at the same time, increasing the yield of H₂. By having more products, the value of the equilibrium constant K increases.

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Chemistry acids and bases
Ket [755]

Answer:

Imma just say acids have more acidity and bases have lower acidity...

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3 years ago
What are complementary pigment colors?
Lisa [10]

Answer:B

Explanation:

omplementary colors are two opposing colors that can be found on the color wheel.

3 0
3 years ago
Read 2 more answers
2 Points<br> What is the oxidation state of Cl in HCIO3?<br> A:+5 <br> B:-1<br> C:+6 <br> D: -7
Olenka [21]

Answer:

The oxidation state of Cl in HCIO3 is <u><em>+5</em></u>

3 0
2 years ago
What is the molarity of the Ca(OH)2 solution if 32.00 mL of Ca(OH)2 requires 16.08 mL of a 2.303 M solution for complete titrati
amm1812

Answer:

For this problem we just need to remember the equation and that the volume is always in liters: MaVa=MbVb

  Ma= 1.338 mol/L Va= 18.75 mL= 0.01875 L Mb= x Vb=24.73 mL= 0.02473 L

 

  So now we can plug into the equation and solve:

   1.338 mol/L * 0.01875 L= x mol/L * 0.02473 L

This is a two step process: stoichiometry and using the answer from the first part to plug and chug it into the Molariy equation.

  First step: setup the stoichiometry problem:

  3.1171 g Na2CO3 * (1 mol/106 g) * (2 mol HCl/ 1 mol Na2CO3)= mol HCl

 

  Second step: Molarity equation

  Molarity= moles HCl/ L   M= mol HCl/0.04027 L

For the third problem, you will just use the same equation as the first: MaVa= MbVb

  Ma=0.57 M   Va= x L   Mb= 0.875 M  Vb= 23.83 mL= 0.02383 L

  0.57 M * x L= 0.875 M * 0.02383 L

With this equation, we want to find the moles of NaOH by using the molarity equation first then because MaVa= MbVb, we know that the number of moles has to be equal.

   0.75 M= x mol/ 0.0227 L    mol NaOH = 0.75 M *0.0227 L         mol NaOH= 0.017025

  So next, we can set it to the mass of the acid using this equation: Molar Mass= mass/ moles

  Molar Mass= 3.6 g/ 0.017025 mol  

 And with that you will find the molar mass of HX, and even determine what X is.

Explanation:

hope I helped

8 0
2 years ago
Find the mass in 2.6 mole of lithium bromide
Tresset [83]

Answer:

2.6 mole of lithium bromide have 225.81 g.

Explanation:

Given data:

Number of moles of lithium bromide = 2.6 mol

Mass of lithium bromide = ?

Solution:

Formula:

<em>Number of moles = mass/ molar mass</em>

Molar mass of lithium bromide = 86.85 g/mol

Mass = number of moles × molar mass

Mass = 2.6 mol ×86.85 g/mol

Mass = 225.81 g

Thus 2.6 mole of lithium bromide have 225.81 g.

5 0
2 years ago
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