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luda_lava [24]
3 years ago
14

How many moles of nitrogen monoxide will be generated when 0.83 moles of nitrogen dioxide gas reacts with water? 3NO2 + H2O 2HNO

3 + NO
Chemistry
2 answers:
Triss [41]3 years ago
5 0

Answer:

0.277

Explanation:

statuscvo [17]3 years ago
4 0
3NO₂ + H₂O→2HNO₃ + NO

n(NO)=n(NO₂)/3

n(NO)=0.83/3=0.277 mol
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Rashid [163]

Answer:

1) The value of Kc:

C. remains the same.

2) The value of Qc:

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3) The reaction must:

B. run in the reverse direction to restablish equilibrium.

4) The concentration of N2 will:

B. decrease.

Explanation:

Hello,

In this case, by means of the Le Chatelier's principle which is based on the shift a chemical reaction could have under some modifications, we have:

1) The value of Kc:

C. remains the same, since it just depend the reaction's thermodynamics as it is computed via:

ln(K)=\frac{\Delta _RG}{RT}

2) The value of Qc:

A. is greater than Kc, since the reaction quotient is:

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Thus, the lower the concentration of ammonia, the higher Qc, making Qc>Kc.

3) The reaction must:

B. run in the reverse direction to restablish equilibrium, since ammonia was withdrawn and should be regenerated to reach the equilibrium.

4) The concentration of N2 will:

B. decrease, since less reactant is forming the products.

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8 0
4 years ago
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How many oxygen atoms are there in the following compound: 2HNO3<br> 3<br> 5<br> 6<br> 12
Fudgin [204]

Answer:

6

Explanation:

There is 2 of the coumpond, in one compound, there are 3 oxygens. But when there are two, it is 6.

7 0
3 years ago
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Based on the activity series of metal, which reaction with water will not happen?
laila [671]

Answer:

B

Explanation:

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5 0
3 years ago
g A radioactive isotope of mercury, 197Hg, decays to gold, 197Au, with a disintegration constant of 0.0108hrs.-1. What % of the
weqwewe [10]

Answer:

7.49% of Mercury

Explanation:

Let N₀ represent the original amount.

Let N represent the amount after 10 days.

From the question given above, the following data were obtained:

Rate of disintegration (K) = 0.0108 h¯¹

Time (t) = 10 days

Percentage of Mercury remaining =?

Next, we shall convert 10 days to hours. This can be obtained as follow:

1 day = 24 h

Therefore,

10 days = 10 day × 24 h / 1 day

10 days = 240 h

Thus, 10 days is equivalent to 240 h.

Finally, we shall determine the percentage of Mercury remaining as follow:

Rate of disintegration (K) = 0.0108 h¯¹

Time (t) = 10 days

Percentage of Mercury remaining =?

Log (N₀/N) = kt /2.303

Log (N₀/N) = 0.0108 × 240 /2.303

Log (N₀/N) = 2.592 / 2.303

Log (N₀/N) = 1.1255

Take the anti log of 1.1255

N₀/N = anti log 1.1255

N₀/N = 13.3506

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N/N₀ = 1/13.3506

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Multiply by 100 to express in percent.

N/N₀ = 0.0749 × 100

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Thus, 7.49% of Mercury will be remaining after 10 days

5 0
3 years ago
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kirill [66]

Answer:

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Explanation:

I am pretty sure you know what sand is, Soda ash is a fine white colored powder that is extracted from the ashes of plants growing in sodium rich soils. Limestone is is a common type of carbonate sedimentary rock.  

4 0
3 years ago
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