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4 years ago

Coulds in space can begin as what ?cloudsplanetsnebulaered giants

2 answers:

6 0

Your answer would be planets because with more of the object combined together to form a major gravity pull can result in a gas or water planet

Ray Of Light [21]4 years ago

5 0

The answer is nebulae, just took the test.

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A boat with a mass of 1000 kg drifts with the current down a straight section of river parallel to the +x+x axis with a speed of

IrinaK [193]

Answer:

Explanation:

Our values are defined by,

$m=1000kg\\v = 2m/s\\a = 2.7 \angle 45\°$

We can express also in a vectorial way, then

$v=2\hat{i} \rightarrow$ no values in $\hat{j}$

Acceleration as follow,

$a= 2.7cos45 \hat{i} + 2.7 sin45 \hat{j}$

We know that velocity is given by,

$V(t) = v_0+at \rightarrow v_0 = 2$

We need to calculate for t=3, then

$v(3) = 2\hat{i} +(2.7cos45 \hat{i} + 2.7 sin45 \hat{j})*3$

$v(3) = (2\hat{i}+3*2.7cos45 \hat{i})+(3*2.7 sin45 \hat{j})$

$v(3) = (2+3*2.7cos45)\hat{i}+(5.7 sin45 )\hat{j}$

$v(3) = 7.7\hat{i}+5.7\hat{j}$

Our mass is 1000Kg, so the momentum is

$P = mv$

$P= 1000(7.7\hat{i}+5.7\hat{j})$

$P=7700\hat{i}+5700\hat{j}$

7 0

4 years ago

A 75.0 W bulb is connected to a

adoni [48]

Answer:

Explanation:

W = 75 watts

V = 110 volts

Formula

W = V * I

Solution

75 = 110 * I Divide by 110

75 / 110 = I

I = 0.6818 Amperes

6 0

3 years ago

Two coherent sources of radio waves, A and B, are 5.00 meters apart. Each source emits waves with wavelength 6.00 meters. Consid

Korolek [52]

Answer:

$z= 2.5 \ m$

$z = (1 \ m , 4 \ m )$

Explanation:

From the question we are told that

Their distance apart is $d = 5.00 \ m$

The wavelength of each source wave $\lambda = 6.0 \ m$

Let the distance from source A where the construct interference occurred be z

Generally the path difference for constructive interference is

$z - (d-z) = m \lambda$

Now given that we are considering just the straight line (i.e points along the line connecting the two sources ) then the order of the maxima m = 0

$z - (5-z) = 0$

=> $2 z - 5 = 0$

=> $z= 2.5 \ m$

Generally the path difference for destructive interference is

$|z-(d-z)| = (2m + 1)\frac{\lambda}{2}$

=> $|2z - d |= (0 + 1)\frac{\lambda}{2}$

=> $|2z - d| =\frac{\lambda}{2}$

substituting values

$|2z - 5| =\frac{6}{2}$

=> $z = \frac{5 \pm 3}{2}$

$z = \frac{5 + 3}{2}$

$z = 4\ m$

and

$z = \frac{ 5 -3 }{2}$

=> $z = 1 \ m$

=> $z = (1 \ m , 4 \ m )$

7 0

3 years ago

A solid sphere of radius R is made of an insulating material. It holds a charge, Q, which is distributed evenly throughout the s

Vinvika [58]

Answer:

The magnitude of Electric Field is $E=\dfrac{Qr}{4\pi \epsilon_0 R^3}$

Explanation:

Given:

Radius of the solid sphere=R
Total charge of the sphere=Q

Let consider a Gaussian surface at a distance of r such that 0<r>R in the shape of sphere such that the electric Field due to this E and it is radially outwards.

The charge inside this Gaussian surface volume we have , $q_{in}=\dfrac{Qr^3}{R^3}$

Now using Gauss Law we have

$E\times4\pi r^2=\dfrac{q_{in}}{\epsilon_0}\\E\times4\pi r^2=\dfrac{\dfrac{Qr^3}{R^3}}{\epsilon_0}\\E=\dfrac{Qr}{4\pi \epsilon_0 R^3}$

5 0

3 years ago

If a grocery cart with a mass of 16.5 kg accelerates at +2.31 m/s2 against a frictional force of -15.0 N, what is the applied fo

ziro4ka [17]

Call the applied force 'A'. (Clever ?)

The forces on the cart are 'A' forward and 15 N backward.

The net force on the art is (A-15) forward.

F = m a

Net forward force = (mass of the cart) x (its forward acceleration)

(A - 15) = (16.5) x (2.31)

A - 15 = 38.115

Add 15 to each side:

<u>A = 53.115 newtons</u>

5 0

3 years ago

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