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const2013 [10]
3 years ago
10

A cow runs left word 50 M to eat some apples then walks left word another 100 and to munch on some flowers the cows total travel

time is 230 S what is the cows average velocity to reach the flowers and what is the cows average speed to reach the flowers
Physics
1 answer:
Lelechka [254]3 years ago
5 0

Answer: velocity = -0.65 speed =0.65

Explanation:

Velocity =speed+direction speed =distance/time

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As a ship comes into view over the horizon the top appears before the rest of the ship how does this demonstrate the earth is sp
valina [46]
Since its a sphere, the top is seen first because its the tallest part if the ship. If the earth was flat, the whole ship would be seen.
7 0
3 years ago
If the force acting on a body of mass 40 k.g is doubled by how much will the acceleration change​
disa [49]

Answer:

Explanation:

Ignoring friction, the acceleration will double

F = ma

2F = m(2a)

7 0
3 years ago
At about 55 meters/sec, a falling parachuter (before the parachute opens) no longer accelerates. Air friction opposes accelerati
JulijaS [17]
The acceleration of gravity on Earth is about 9.8 m/s².
That means that if air resistance is neglected, a falling body
smoothly gains 9.8 m/s of downward speed each second.

If our intrepid chutist lightly stepped out of the plane or was
gently pushed, so that his initial downward speed was zero
and grew by 9.8 m/s every second, then it took him ...

               (55) / (9.8)  =  5.6 seconds

to reach that particular downward speed.
3 0
3 years ago
Estimate the speed of the water free surface and the time required to fill with water a cone-shaped container 1.5 m high and 1.5
Zolol [24]

Answer:

speed of water is 0.0007138m/s

Explanation:

From the law of conservation of mass

Rate of mass accumulation inside vessel = mass flow in - mass flow out

so, dm/dt = mass flow in - mass flow out

taking p as density

d \frac{dQ}{dt} = pq_i_n

where,

q(in) is the volume flow rate coming in

Q = is the volume of liquid inside tank at any time

But,

dQ = Adh

where ,

A = area of liquid surface at time t

h = height from bottom at time t

A = πr²

r is the radius of liquid surface

r = (1.5/2) \div 1.5 h = \frac{h}{2}

Hence,

\pi( \frac{h}{2} )^2\frac{dh}{dt} =q_i_n

\frac{dh}{dt} = \frac{q_i_n}{\pi (\frac{h}{2})^2 } =\frac{4q_i_n}{\pi h^2}

so, the speed of water surface at height h

v = \frac{dh}{dt} =\frac{4q_i_n}{\pi h^2}

where,

q_i_n is 75.7 L/min = 0.0757m³/min

h = 1.5m

so,

v = \frac{4 \times 0.0757}{\pi \times 1.5^2} \\\\v = 0.04283m/min

v = 0.04283 /60

v = 0.0007138m/s

Hence, speed of water is 0.0007138m/s

5 0
3 years ago
Pleas ehelp about convergent boundaries and don't spam I really need help on a few question PLLLLLLZZZ
Lapatulllka [165]
I Don’t know I’m so sorry
8 0
3 years ago
Read 2 more answers
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