Answer:
Explanation:
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In this case, since these problems about gas mixtures are based off Dalton's law in terms of mole fraction, partial pressure and total pressure, we can write the following for hydrogen, we are given its partial pressure:
And can be solved for the total pressure as follows:
However, we first calculate the mole fraction of hydrogen by subtracting that of nitrogen to 1 due to:
Then, we can plug in to obtain the total pressure:
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Answer:
Explanation:
A sound knowledge of specific heat capacity of the metals is required in this case.
The specific heat capacity of a metal is the quantity of heat required to the raise the temperature of a unit mass of it by 1°C.
It is related to quantity of heat using the expression below;
H = m c Δt
where m is the mass
c is the specific heat capacity
Δt is the temperature change
let us make the specific the subject of the expression;
c =
we can see that there is an inverse relationship between specific heat and temperature change.
The specific heat capacity of a body is an intensive property that is unique to the metal.
The higher the specific heat capacity, the lower the amount of temperature change in it.
Let us find the specific heat capacity of the given metals;
Aluminium 0.897J/gK
Iron 0.412J/gK
Silver 0.24J/gK
After the heat is supplied,
Silver > Iron > Aluminium in terms of temperature change
The molarity of a solution that has 26 moles of NaCl in 2.7L of water is 9.63M.
<h3>How to calculate molarity?</h3>
The molarity of a solution can be calculated by dividing the number of moles of the solute by the volume of the solution as follows:
Molarity = no of moles ÷ volume
According to this question, a solution has 26 moles of NaCl in 2. 7 l of water. The molarity is as follows:
Molarity = 26mol ÷ 2.7L
Molarity = 9.6M.
Therefore, the molarity of a solution that has 26 moles of NaCl in 2.7L of water is 9.63M.
Learn more about molarity at: brainly.com/question/2817451
We need to measure 20.0 grams of CaCl₂ to prepare 500 mL of 0.360 M solution.
First, we need to determine the required moles of CaCl₂. We have 500 mL (0.500 L) of a 0.360 M solution (0.360 moles of CaCl₂ per liter of solution).
Then, we will convert 0.180 moles to grams using the molar mass of CaCl₂ (110.98 g/mol).
To prepare the solution, we weigh 20.0 g of CaCl₂ and add it to a beaker with enough distilled water to dissolve it. We stir it, heat it if necessary, and when we have a solution, we transfer it to a 500 mL flask and complete it to the mark with distilled water.
We need to measure 20.0 grams of CaCl₂ to prepare 500 mL of 0.360 M solution.
You can learn more about solutions here: brainly.com/question/2412491