3 years ago

(03.02 LC)

Physics

1 answer:

ratelena [41]3 years ago

5 0

Answer:

O Adenine and guanine

Explanation:

i think tell me if im rong

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If a cat can exert 2000N Of Force to move a trailer 50m is 20 seconds how much power did the car use ?

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provides one model for solving this problem. The maximum strength of the earth's magnetic field is about 6.9 x 10-5 T near the s

jeka57 [31]

Answer:

The minimum no. of turns is $3.126 \times 10^{5}$

Explanation:

Given:

Magnetic field $B = 6.9 \times 10^{-5}$ T

Frequency $f = 84.5$ Hz

Area of turn $A = 0.021$ $m^{2}$

Voltage $V_{rms} = 170$ V

From the formula of induced emf,

$V = NBA \omega$

Where $\omega = 2\pi f$ and $V = \sqrt{2} V_{rms}$

So number of turn is,

$N = \frac{\sqrt{2} V_{rms} }{AB2\pi f }$

$N = \frac{\sqrt{2} \times 170 }{0.021 \times 6.9 \times 10^{-5} \times 6.28 \times 84.5 }$

$N = 3.126 \times 10^{5}$

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3 years ago

Calculate the wavelength of 26 GeV electrons. Express your answer using two significant figures. λ = m

Alenkinab [10]

Answer:

4.78 x 10^-17 m

Explanation:

E = 26 GeV

First convert GeV into J

1 GeV = 1.6 x 10^-10 J

E = 26 x 1.6 x 10^-10 = 41.6 x 10^-10 J

Use the formula for energy

E = h c / λ

Where, h is the Plank's constant and λ be the wavelength and c be the velocity of light.

λ = h c / E

λ = ( 6.63 x 10^-34 x 3 x 10^8) / (41.6 x 10^-10)

λ = 4.78 x 10^-17 m

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3 years ago

(eopt)s. Find the power dissipated in a 25 r heater<br>connected to a 220V outer.

Alex Ar [27]

Answer:

P = 1936 W

Explanation:

Given that,

Voltage, V = 220 V

The resistance of the heater, R = 25 ohms

We need to find the power dissipated in the heater. We know that the power dissipated by the electric appliances is given by :

$P=\dfrac{V^2}{R}\\\\P=\dfrac{(220)^2}{25}\\\\P=1936\ W$

So, the required power is equal to 1936 W.

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3 years ago