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Zarrin [17]
3 years ago
5

If the pressure of a gas is 2.42 atm, what is its pressure in kPa?

Chemistry
2 answers:
Inessa [10]3 years ago
4 0
KPa = atm x 101.325
kPa = 2.42 x 101.325
kPa = 245
Lina20 [59]3 years ago
4 0

Answer is: 245 kPa.

1 atm = 101.325 kPa.

p = 2.42 atm; the pressure of the gas.

p = 2.42 atm · 101.325 kPa/atm.

p = 245.20 kPa.

Atmospheric pressure (atm) is the force per unit area by the weight of air above that point.

Kilopascal (kPa) is a metric system pressure unit and equals to 1000 force of newton per square meter.

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Hello..................<br><br>.....​
VashaNatasha [74]

Hello.....

Have a beautiful and joyful day ahead.

3 0
2 years ago
A 0.216 g sample of carbon dioxide, CO2, has a volume of 507 mL and a pressure of 470 mmHg. What is the temperature of the gas i
Gala2k [10]

Answer:

The temperature of the gas is 876.69 Kelvin

Explanation:

Ideal gases are a simplification of real gases that is done to study them more easily. It is considered to be formed by point particles, do not interact with each other and move randomly. It is also considered that the molecules of an ideal gas, in themselves, do not occupy any volume.

The pressure, P, the temperature, T, and the volume, V, of an ideal gas, are related by a simple formula called the ideal gas law:  

P*V = n*R*T

where P is the gas pressure, V is the volume that occupies, T is its temperature, R is the ideal gas constant, and n is the number of moles of the gas.

In this case:

  • P= 470 mmHg
  • V= 570 mL= 0.570 L
  • n= 0.216 g= 0.0049 moles (being the molar mass of carbon dioxide is 44 g/mole)
  • R= 62.36367 \frac{mmHg*L}{mol*K}
  • T=?

Replacing:

470 mmHg*0.570 L= 0.0049 moles* 62.36367 \frac{mmHg*L}{mol*K} *T

Solving:

T=\frac{470 mmHg*0.570 L}{0.0049 moles* 62.36367\frac{mmHg*L}{mol*K} }

T= 876.69 K

<em><u>The temperature of the gas is 876.69 Kelvin</u></em>

6 0
3 years ago
Kinetic energy is energy of motion. What below is considered to be a form of kinetic energy?
gregori [183]

Answer:

In physics, the kinetic energy of an object is the energy that it possesses due to its motion It is defined as the work needed to accelerate a body of a given mass from rest to its stated velocity Having gained this energy during its acceleration the body maintains this kinetic energy unless its speed changes

Example:

A semi-truck travelling down the road

A river flowing at a certain speed

5 0
3 years ago
how many ml of a 22.5% (v/v) ethanol solution would you need to measure out in order to have 12.5 ml of ethanol ?
Aleks [24]
Volume percent<span> or </span>volume/volume percent<span> (v/v%) is used when preparing solutions of liquids. It will have units of volume of the smaller composition substance over the volume of the solution. We calculate as follows:

12.5 mL ethanol = .225 mL ethanol / 1 mL solution ( V )
V = 55.56 mL of the 22.5 % by volume ethanol solution is needed

Hope this answers the question.</span>
8 0
4 years ago
Calculate the molarity of a solution that contains 3.00 grams Na2SO4 in 25 mL of solution.
Naddik [55]

Answer:

M Na2SO4 sln = 0.8448 M

Explanation:

  • molarity (M) [=] mol/L

∴ mass Na2SO4 = 3.00 g

∴ volume soln = 25 mL = 0.025 L

∴ molar mass Na2SO4 = 142.04 g/mol

⇒ mol Na2SO4 = (3.00 g)*(mol/142.04 g) = 0.02112 mol

⇒ M Na2SO4 sln = (0.02112 mol/0.025 L ) = 0.8448 M

3 0
4 years ago
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