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3 years ago

A resistor has a resistance of 50 Ohms. If a 9V battery is connected to it, how much current flows in the wire?

Physics

1 answer:

Ksju [112]3 years ago

7 0

Answer:

0.18 amperes

Explanation:

V = 9

R = 50 ohms

I = ?

Formula

V = I * R

Solution

9 = I * 50 Divide by 50. Switch

I = 9 / 50

I = 0.18 amperes.

If you know what a milliampere is then it is 180 ma which is very large for a 9 volt battery to handle

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Frank has a sample of steel that weighs 80 grams. If the density of his sample of steel is 8 g/cm3, what is the sample’s volume?

FrozenT [24]

Should be 10 cm cubed

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3 years ago

Read 2 more answers

A car is moving with speed 20 m/s and acceleration 2 m/s2 at a given instant. Using a second-degree Taylor polynomial, estimate

PilotLPTM [1.2K]

Answer:

$T(1)=21$

Explanation:

The equation of the position in kinematics is given:

$x(t)=x_{0}+v_{0}t+0.5at^{2}$

x(0) is the initial position, in this it is 0
v(0) is the initial velocity (20 m/s)
a is the acceleration (2 m/s²)

So the equation will be:

$x(t)=20t+0.5*2*t^{2}$

$x(t)=20t+t^{2}$

Now, the Taylor polynomial equation is:

$f(a)+\frac{f'(a)}{1!}(x-a)+\frac{f''(a)}{2!}(x-a)^{2}+...$

Using our position equation we can find f'(t)=v(t) and f''(x)=a(t). In our case a=0, so let's find each derivative.

$f(t)=x(t)=20t+t^{2}$

$f'(t)=\frac{dx(t)}{dt}=v(t)=20+2t$

$f''(t)=\frac{dv(t)}{dt}=a(t)=2$

Using the Taylor polynomial with a = 0 and take just the second order of the derivative.

$f(0)+\frac{f'(0)}{1!}(x)+\frac{f''(0)}{2!}(x)^{2}$

$f(0)=x(0)=0$

$f'(0)=v(0)=20$

$f''(0)=a(0)=2$

$T(t)=f(0)+\frac{f'(0)}{1!}(t)+\frac{f''(0)}{2!}(t)^{2}$

$T(t)=\frac{20}{1!}(t)+\frac{2}{2!}(t)^{2}$

$T(t)=20t+t^{2}$

Let's put t=1 so find the how far the car moves in the next second:

$T(1)=20*1+1^{2}$

$T(1)=21$

Therefore, the position in the next second is 21 m.

We need to know if the acceleration remains at this value to use this polynomial in the next minute, so I suggest that it would be reasonable to use this method just under this condition.

I hope it helps you!

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3 years ago

a 100 kg person travels from sea level to an altitude of 5000 m. By how mans newtons does their weight change?

Bumek [7]

Answer:

Thus, the change in the weight of the person is 1.6N , option c is correct.

Explanation:

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2 years ago

The Sankey diagrams below show the energy transfers in two light bulbs. What is the efficiency of light bulb 1? 1: 80j Input ene

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Answer:

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3 years ago

Please help! Please explain how and why you have changed the units to kg m^-3. Thank you

PIT_PIT [208]

Answer:

2500 kg/m³

Explanation:

The density is ...

(107 g)/((12.2 cm)(3.7 cm)(0.95 cm)) = 107/42.883 g/cm³ ≈ 2.5 g/cm³

In kg/m³, the density is ...

(2.5 g/cm³)×(1 kg/(1000 g))×(100 cm/m)³ = 2500 kg/m³

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