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Advocard [28]
3 years ago
14

Which of the following ions is formed when a base is dissolved in a solution?

Chemistry
1 answer:
Fofino [41]3 years ago
7 0

Answer:

j1kjfifirjfiffififkffkfjjfjfjfjffntjkffjfjdkdkdkdmdkd

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Gloria is writing the chemical formula for a compound using its chemical name. She has just identified the names of the elements
disa [49]
She will use the periodic table of elements to not only find out the chemical symbols of the elements written within the name, but also to check whether or not the elements are metals and or nonmetals, from this determine the ionic charges if needed for metals, and for metals that have more than one ionic charge, use a Roman numeral to represent the ionic charge that she would be using in writing the chemical formula of the compound.
5 0
4 years ago
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Name the element that is found in the third period and in the same family as Nitrogen
olchik [2.2K]

Answer:

Phosphorus

Explanation:

Phosphorus is found directly under nitrogen on the periodic table in the third period and 15th group.

4 0
3 years ago
Be sure to answer all parts. A concentration cell consists of two Sn/Sn2+ half-cells. The electrolyte in compartment A is 0.23 M
kolbaska11 [484]

Answer:

Part A. The half-cell B is the cathode and the half-cell A is the anode

Part B. 0.017V

Explanation:

Part A

The electrons must go from the anode to the cathode. At the anode oxidation takes place, and at the cathode a reduction, so the flow of electrons must go from the less concentrated solution to the most one (at oxidation the concentration intends to increase, and at the reduction, the concentration intends to decrease).

So, the half-cell B is the cathode and the half-cell A is the anode.

Part B

By the Nersnt equation:

E°cell = E° - (0.0592/n)*log[anode]/[cathode]

Where n is the number of electrons being changed in the reaction, in this case, n = 2 (Sn goes from S⁺²). Because the half-reactions are the same, the reduction potential of the anode is equal to the cathode, and E° = 0 V.

E°cell = 0 - (0.0592/2)*log(0.23/0.87)

E°cell = 0.017V

3 0
4 years ago
A 3.0 L cointainer contains 4 mol He, 2 mol Ne,and 1 mol Ar. What is the mole fraction of neon gas? What is the partial pressure
CaHeK987 [17]

Answer:

Partial pressure of Ne = 1.43 atm

Explanation:

Step 1: Data given

Volume = 3.0 L

Number of moles He = 4 moles

Number of moles Ne = 2 moles

Number of moles Ar = 1 mol

Total pressure = 5 atm

Step 2: Calculate total moles

Total moles = 4 moles + 2 moles + 1 mol

Total moles = 7 moles

Step 3: Calculate the mol ratio

Mol ratio = moles / total mol

Mol ratio He = 4 moles / 7 moles = 0.571

Mol ratio Ne = 2 moles / 7 moles = 0.286

Mol ratio Ar = 1 mol / 7 moles = 0.143 moles

Ste p4: Calculate partial pressure

PArtial pressure = mol ratio * total pressure

Partial pressure of Ne = mol ratio Ne * total pressure

Partial pressure of Ne = 0.286 * 5 atm

Partial pressure of Ne = 1.43 atm

8 0
3 years ago
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How is the number of neutrons and in nucleus of an atom calculated
Sav [38]
The number of neutrons in an atoms nucleus can be calculated by subtracting the atomic number of that atom from its mass number.

(mass number  -  atomic number = number of neutrons)
7 0
3 years ago
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