Which of the following ions is formed when a base is dissolved in a solution?
1 answer:
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Answer:
Moles of = 6 moles
Explanation:
The reaction of and
to make
is:
⇒
The above reaction shows that 2 moles of Sc can react with 3 moles of to form
Mole Ratio= 2:3
For 10 moles of Sc we need:
Moles of =
Moles of =
Moles of =15 moles
So 15 moles of are required to react with 10 moles of
but we have 9 moles of
, it means
is limiting reactant.
Moles of ScCl_3= 6 moles
Answer:
1.327 g Ag₂CrO₄
Explanation:
The reaction that takes place is:
- 2AgNO₃(aq) + K₂CrO₄(aq) → Ag₂CrO₄(s) + 2KNO₃(aq)
First we need to <em>identify the limiting reactant</em>:
We have:
- 0.20 M * 50.0 mL = 10 mmol of AgNO₃
- 0.10 M * 40.0 mL = 4 mmol of K₂CrO₄
If 4 mmol of K₂CrO₄ were to react completely, it would require (4*2) 8 mmol of AgNO₃. There's more than 8 mmol of AgNO₃ so AgNO₃ is the excess reactant. <em><u>That makes K₂CrO₄ the limiting reactant</u></em>.
Now we <u>calculate the mass of Ag₂CrO₄ formed</u>, using the <em>limiting reactant</em>:
- 4 mmol K₂CrO₄ *
= 1326.92 mg Ag₂CrO₄
- 1326.92 mg / 1000 = 1.327 g Ag₂CrO₄