Answer:
the answer is over water D
The air pressure inside the can is lower compared to that of outside air pressure.
Explanation:
- In general, the air pressure of an already opened can will be the same as the outside pressure.
- Since the can is evacuated and remain as vacuum, so there will be no pressure difference in it.
- If the can opens, air inside the can push the top and escapes to the outside.
- This is due to high pressure experienced outside the can compare to that of lower pressure inside the can and this may even cause can to collapse itself.
Kc = 3.2
The chemical equation is
2H2S ⇌ 2H2 + S2
The equilibrium constant expression is
<em>K</em>c ={[H2]^2[S2]}/[H2S]^2
1. Calculate the <em>equilibrium concentrations</em> of each component
[H2] = (4.0 mol)/(4.0 L) = 1.0 mol/L
[S2] = (0.80 mol)/(4.0 L) = 0.20 mol/L
[H2S] = (1.0 mol)/(4.0 L) = 0.25 mol/L
2. Calculate the value of the <em>equilibrium constant</em>
<em>K</em>c = (1.0^2 x 0.20)/0.25^2 = 3.2
The answer is (C) 2 hydrogen atoms
Answer:
you have school on Sunday?
