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ollegr [7]
3 years ago
7

A feather and a minivan are dropped vertically downward from a height of twenty meters and both are subject to air drag as they

fall. The minivan reaches the ground much faster than the feather. Which one of the following statements concerning this situation is true, if any?
a) The minivan has a larger terminal velocity than the feather because it experiences less air resistance than the feather.

b) The minivan encounters a smaller force of air resistance than the feather and falls faster.

c) Each object experiences the same amount of air drag, but the minivan experiences the greatest force of gravity.

d) The feather experiences more air drag than the minivan and has a smaller terminal velocity.
Physics
1 answer:
Luda [366]3 years ago
6 0

Answer:

maybe C i'm not 100% sure

I'm sorry if this didn't help

Explanation:

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MA_775_DIABLO [31]

Answer:

a)   D_ total = 18.54 m,   b)        v = 6.55 m / s

Explanation:

In this exercise we must find the displacement of the player.

a) Let's start with the initial displacement, d = 8 m at a 45º angle, use trigonometry to find the components

           sin 45 = y₁ / d

           cos 45 = x₁ / d

           y₁ = d sin 45

           x₁ = d sin 45

           y₁ = 8 sin 45 = 5,657 m

           x₁ = 8 cos 45 = 5,657 m

The second offset is d₂ = 12m at 90 of the 50 yard

            y₂ = 12 m

            x₂ = 0

total displacement

          y_total = y₁ + y₂

          y_total = 5,657 + 12

          y_total = 17,657 m

          x_total = x₁ + x₂

          x_total = 5,657 + 0

          x_total = 5,657 m

          D_total =   17.657 i^+ 5.657 j^  m

          D_total = Ra (17.657 2 + 5.657 2)

          D_ total = 18.54 m

b) the average speed is requested, which is the offset carried out in the time used

           v = Δx /Δt

the distance traveled using the pythagorean theorem is

         r = √ (d1² + d2²)

          r = √ (8² + 12²)

          r = 14.42 m

The time used for this shredding is

         t = t1 + t2

         t = 1 + 1.2

         t = 2.2 s

let's calculate the average speed

         v = 14.42 / 2.2

         v = 6.55 m / s

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