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just olya [345]
4 years ago
8

An object moves in simple harmonic motion with amplitude 11m and period 4 minutes. At time t = 0 minutes, its displacement d fro

m rest is -11m, and initially, it moves in a positive direction. Give the equation modeling the displacement d as a function of time t.d = ?
Physics
1 answer:
Sergio039 [100]4 years ago
8 0

Answer:

Explanation:

Angular velocity ω = 2π / T = 2 x 3 . 14 / (4 x 60 ) = .026 rad / s.

d = D Sin ( ωt + θ )  where  D = amplitude = 11 m θ = initial phase.

-11 = 11 sin ( 0 + θ ) = sin θ = -1 , θ = - π /2

So, d = D Sin ( ωt - θ )

         d = 11  Sin ( .026 t -  π /2  ) is the required equation.

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The average speed in m/s of a person that jogs eight complete laps around a 400m track in a total time of 15.1 min is 0.44m/s.

<h3>How to calculate average speed?</h3>

Average speed of a moving body can be calculated by dividing the distance moved by the time taken.

Average speed = Distance ÷ time

According to this question, a person jogs eight complete laps around a 400m track in a total time of 15.1 min. The average speed is calculated as follows:

15.1 minutes in seconds is as follows = 906 seconds

Average speed = 400m ÷ 906s

Average speed = 0.44m/s

Therefore, the average speed in m/s of a person that jogs eight complete laps around a 400m track in a total time of 15.1 min is 0.44m/s.

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lbvjy [14]

Answer:

a)9.5\frac{ft}{s^2}\\ b) 12.66\frac{ft}{s^2}

Explanation:

A body has acceleration when there is a change in the velocity vector, either in magnitude or direction. In this case we only have a change in magnitude. The average acceleration represents the speed variation that takes place in a given time interval.

a)

a_{avg}=\frac{\Delta v}{\Delta t}\\a_{avg}=\frac{v_{f}-v_{i}}{t_{f}- t_{i}}\\a_{avg}=\frac{38\frac{ft}{s}-0}{4 s- 0}=9.5\frac{ft}{s^2}\\

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a_{avg}=\frac{\Delta v}{\Delta t}\\a_{avg}=\frac{v_{f}-v_{i}}{t_{f}- t_{i}}\\a_{avg}=\frac{76\frac{ft}{s}-38\frac{ft}{s}}{7 s- 4s}\\a_{avg}=\frac{38\frac{ft}{s}}{3s}=12.66\frac{ft}{s^2}

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