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kicyunya [14]
3 years ago
14

Find the specific heat of an unknown material with an initial temperature of 20°C, when 5000 Joules are applied to a 50 gram sam

ple and the final temperature is 70°C
Chemistry
1 answer:
xxTIMURxx [149]3 years ago
8 0

Answer:

2J/g°C

Explanation:

Q = 5000J

Initial temperature (T1) = 20°C

Final temperature (T2) = 70°C

Specific heat capacity (c) = ?

Heat energy (Q) = mc∇T

Q = mc∇T

Q = mc(T2 - T1)

5000 = 50 × c × (70 - 20)

5000 = 50c × 50

5000 = 2500c

c = 5000 / 2500

c = 2J/g°C

The specific heat capacity of the substance is 2J/g°C

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The coefficient for NaNO₃ = 6

<h3>Further explanation </h3>

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AI(NO₃)₃ +Na₂SO₄ → Al₂(SO₄) + NaNO₃

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What is true about elements that are in the same column group or family
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