Let us assume that this molecule is 100 percent ionic. In that case, the charges are distinguished by a bond length.
h = Q × r
= (160 × 10⁻¹⁹ c) (127 × 10⁻¹² m) (10 / 3.336 × 10⁻³⁰ cm)
= 6.09 D.
The actual dipole moment is = 1.08 D
Therefore, the percent ionic character is,
= 1.08 D / 6.09 D × 100
= 17.7 %.
Answer: Thus the concentration of the sulfuric acid is 0.1201 M
Explanation:
To calculate the concentration of acid, we use the equation given by neutralization reaction:
where,
are the n-factor, molarity and volume of acid which is 
are the n-factor, molarity and volume of base which is NaOH.
We are given:
Putting values in above equation, we get:
Thus the concentration of the sulfuric acid is 0.1201
Hey did you ever find the answers to this?
elements using your lessons and experience within this virtual lab. 150 words max its a
The orbital is the probable location of the electron of an atom.
Always remember the difference between Bohr and wave-mechanical model in terms of electrons!
Your questions answer is Electron!
But you should also know Bohr said electrons are in orbitals in a fixed proportion, but modern wave mechanical disagrees with this and said electrons are arranged in a very complex random proportion in a region called orbital!
Hope this helped
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