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Novosadov [1.4K]

3 years ago

7

and area' Explain the following in your answers, use the words pressure', 'force A truck used in the desert has wide tyres. 6 A

cricket stump has a sharp point at one end. c A drawing pin has a sharp point at one end and a large, flat head at the other broad head force sharp point

1 answer:

nlexa [21]3 years ago

4 0

Answer:

a cricket stamp

Explanation:

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A uniform disk with a mass of 5.0 kg and diameter 30 cm rotates on a frictionless fixed axis through its center and perpendicula

igomit [66]

Answer:

Angular acceleration of the disk will be $\alpha =10.714rad/sec^2$

Explanation:

We have given mass of the disk m = 5 kg

Diameter of the disk d = 30 cm = 0.3 m

So radius $r=\frac{d}{2}=\frac{0.3}{2}=0.15m$

Moment of inertia of disk is given by $I=\frac{1}{2}mr^2=\frac{1}{2}\times 5\times 0.15^2=0.056kgm^2$

Force is given by F=4 N

Torque is given as $\tau =Fr=4\times 0.15=0.6N-m$

We also know that torque is given by $\tau =I\alpha$

$0.6=0.056\times \alpha$

$\alpha =10.714rad/sec^2$

5 0

3 years ago

Lake Erie contains roughly 4.00 ✕ 1011 m3 of water. (a) How much energy is required to raise the temperature of that volume of w

denis-greek [22]

Answer:

Part a)

$Q = 6.36 \times 10^{18} J$

Part b)

$t = 144.11 years$

Explanation:

Part a)

Energy required to raise the temperature of water from 17.8 degree C to 21.6 degree C is given by formula

$Q = ms\Delta T$

here we know that

Here the volume of the water is given as

$V = 4.00 \times 10^{11} m^3$

now the mass of water is

$m = density \times volume$

$m = 4.00 \times 10^{14} kg$

now the heat required is

$Q = (4 \times 10^{14})(4186)(21.6 - 17.8)$

$Q = 6.36 \times 10^{18} J$

Part b)

As we know that power is supplied at

$P = 1400 MW$

so here we know

$P = \frac{Q}{t}$

so here we have

$t = \frac{Q}{P}$

$t = \frac{6.36 \times 10^{18}}{1400 \times 10^6}$

$t = 4.54 \times 10^9 s$

$t = 144.11 years$

7 0

3 years ago

Covalent Bonds usually bond atoms of which type of elements together?

anzhelika [568]

<h2>Answer: Nonmetals to Nonmetals </h2>

Covalent bonds hold non-metallic atoms together. These atoms have many electrons in their outermost level and have a tendency to gain electrons rather than to yield them.

In this case the bond is formed by sharing a pair of electrons between the two atoms, one from each atom. Then, this pair of shared electrons is common to the two atoms and holds them together, so that both atoms acquire more stability.

Therefore the correct answer is C.

5 0

3 years ago

what is the equation for newton’s second law of motion, in terms of mass, velocity and time, when the mass of the system is cons

Sergio039 [100]

Answer:

Newton's second law of motion is F = ma, or force is equal to mass times acceleration.

6 0

3 years ago

You are watching an archery tournament when you start wondering how fast an arrow is shot from the bow. Remembering your physics

spayn [35]

Answer:

$v_0 = 3.53~{\rm m/s}$

Explanation:

This is a projectile motion problem. We will first separate the motion into x- and y-components, apply the equations of kinematics separately, then we will combine them to find the initial velocity.

The initial velocity is in the x-direction, and there is no acceleration in the x-direction.

On the other hand, there no initial velocity in the y-component, so the arrow is basically in free-fall.

Applying the equations of kinematics in the x-direction gives

$x - x_0 = v_{x_0} t + \frac{1}{2}a_x t^2\\63 \times 10^{-3} = v_0t + 0\\t = \frac{63\times 10^{-3}}{v_0}$

For the y-direction gives

$v_y = v_{y_0} + a_y t\\v_y = 0 -9.8t\\v_y = -9.8t$

Combining both equation yields the y_component of the final velocity

$v_y = -9.8(\frac{63\times 10^{-3}}{v_0}) = -\frac{0.61}{v_0}$

Since we know the angle between the x- and y-components of the final velocity, which is 180° - 2.8° = 177.2°, we can calculate the initial velocity.

$\tan(\theta) = \frac{v_y}{v_x}\\\tan(177.2^\circ) = -0.0489 = \frac{v_y}{v_0} = \frac{-0.61/v_0}{v_0} = -\frac{0.61}{v_0^2}\\v_0 = 3.53~{\rm m/s}$

6 0

3 years ago