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Marta_Voda [28]
3 years ago
8

which of the following is not used to protect us from the possibility of receiving an electric shock​

Physics
1 answer:
Juli2301 [7.4K]3 years ago
6 0

Answer:water

Explanation:

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What type of relationship exists between the altitude and the atmospheric density, and what would the atmospheric density be at
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5 0
3 years ago
A young diver is practicing his skills before an important team competition. Use the diagram below in order to analyze the energ
skad [1K]
  • Mass of the diver (m) = 90 Kg.
  • Height of the board from the ground (h) = 10 m.
  • Acceleration due to gravity (g) = 9.8 m/s^2.
  • Height of the diver from the ground when he reaches point C (x) = 5m
  • Initial velocity (u) = 0 m/s
  • We know, gravitational potential energy of a body = mass × acceleration due to gravity × height.
  • Therefore, the gravitational potential energy of the diver when he reaches point C (GPE) = mg(h - x)
  • or, GPE = [90 × 9.8 × (10-5)] J
  • or, GPE = [90 × 9.8 × 5] J
  • or, GPE = 4410 J
  • For a freely falling body,
  • v^2 - u^2 = 2gh
  • or, v^2 = 2gh
  • We know, kinetic energy of a body = 1/2 mv^2
  • Therefore, kinetic energy of the diver when he reaches point C (KE) = 1/2 m(2gx)
  • Here, 2gx = (2 × 9.8 × 5) = 98 (m/s)^2
  • We have already seen v^2 = 2gh
  • or, v = √2gh
  • So, the velocity of the diver = √2gx = √98 m/s = 9.9 m/s

<u>Answers:</u>

<em><u>The </u></em><em><u>gravitational</u></em><em><u> potential</u></em><em><u> energy</u></em><em><u> of</u></em><em><u> the</u></em><em><u> </u></em><em><u>diver </u></em><em><u>when </u></em><em><u>he</u></em><em><u> reaches</u></em><em><u> point</u></em><em><u> C</u></em><em><u> </u></em><em><u>is </u></em><em><u>4</u></em><em><u>4</u></em><em><u>1</u></em><em><u>0</u></em><em><u> </u></em><em><u>J.</u></em>

<em><u>The </u></em><em><u>velocity</u></em><em><u> </u></em><em><u>of </u></em><em><u>the </u></em><em><u>diver </u></em><em><u>is </u></em><em><u>9</u></em><em><u>.</u></em><em><u>9</u></em><em><u> </u></em><em><u>m/</u></em><em><u>s.</u></em>

Hope you could get an idea from here.

Doubt clarification - use comment section.

5 0
2 years ago
Read 2 more answers
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