Solids
Hope this helped:)
Because the scientific method can go around in a circle as many times as neccisary to get the results you need
Answer:
So this means an increase in either will decrease the other factor like density is mass per unit volume and it's also difficult to calculate with only altitude of 1,291 kilometers that's given.
Explanation:
Answer:
the law of conservation of mass and the law of constant compositionthe law of conservation of mass and the law of constant composition
- Mass of the diver (m) = 90 Kg.
- Height of the board from the ground (h) = 10 m.
- Acceleration due to gravity (g) = 9.8 m/s^2.
- Height of the diver from the ground when he reaches point C (x) = 5m
- Initial velocity (u) = 0 m/s
- We know, gravitational potential energy of a body = mass × acceleration due to gravity × height.
- Therefore, the gravitational potential energy of the diver when he reaches point C (GPE) = mg(h - x)
- or, GPE = [90 × 9.8 × (10-5)] J
- or, GPE = [90 × 9.8 × 5] J
- or, GPE = 4410 J
- For a freely falling body,
- v^2 - u^2 = 2gh
- or, v^2 = 2gh
- We know, kinetic energy of a body = 1/2 mv^2
- Therefore, kinetic energy of the diver when he reaches point C (KE) = 1/2 m(2gx)
- Here, 2gx = (2 × 9.8 × 5) = 98 (m/s)^2
- We have already seen v^2 = 2gh
- or, v = √2gh
- So, the velocity of the diver = √2gx = √98 m/s = 9.9 m/s
<u>Answers:</u>
<em><u>The </u></em><em><u>gravitational</u></em><em><u> potential</u></em><em><u> energy</u></em><em><u> of</u></em><em><u> the</u></em><em><u> </u></em><em><u>diver </u></em><em><u>when </u></em><em><u>he</u></em><em><u> reaches</u></em><em><u> point</u></em><em><u> C</u></em><em><u> </u></em><em><u>is </u></em><em><u>4</u></em><em><u>4</u></em><em><u>1</u></em><em><u>0</u></em><em><u> </u></em><em><u>J.</u></em>
<em><u>The </u></em><em><u>velocity</u></em><em><u> </u></em><em><u>of </u></em><em><u>the </u></em><em><u>diver </u></em><em><u>is </u></em><em><u>9</u></em><em><u>.</u></em><em><u>9</u></em><em><u> </u></em><em><u>m/</u></em><em><u>s.</u></em>
Hope you could get an idea from here.
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