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3 years ago

Where is visible light found on the electromagnetic spectrum?

Physics

1 answer:

vampirchik [111]3 years ago

5 0

Answer:

C: in between infrared and ultraviolet light

Explanation:

the colors are

V - violet

I - indigo

B - blue

G - green

Y - yellow

O - orange

R - red

You might be interested in

Which is most likely a covalent compound? LiF MgS NH3 CaCl2

Artemon [7]

Answer:

NH₃

Explanation:

The compound that is covalent from the given choices is NH₃.

Covalent compounds are usually formed between two atoms with similar values of electronegativities such that the difference is very small or zero.

This bond type involves the sharing of electrons between two atoms with similar electronegativities.
Nitrogen and hydrogen forms stable configuration that are isoelectronic with noble gases by sharing their valence electrons.
The 3 hydrogen electrons are enough to make nitrogen isoelectronic with neon.
Also, the nitrogen with 3 lone pairs of electrons provides the bonding hydrogen with needed electrons to attain a structure similar to helium.

8 0

3 years ago

Read 2 more answers

A 0.5 μF and a 11 μF capacitors are connected in series. Then the pair are connected in parallel with a 1.5 μF capacitor. What i

NISA [10]

Answer:

$C_{eq}=1.97\ \mu F$

Explanation:

Given that,

Capacitance 1, $C_1=0.5\ \mu F$

Capacitance 2, $C_2=11\ \mu F$

Capacitance 3, $C_3=1.5\ \mu F$

C₁ and C₂ are connected in series. Their equivalent is given by :

$\dfrac{1}{C'}=\dfrac{1}{C_1}+\dfrac{1}{C_2}$

$\dfrac{1}{C'}=\dfrac{1}{0.5}+\dfrac{1}{11}$

$C'=0.47\ \mu F$

Now C' and C₃ are connected in parallel. So, the final equivalent capacitance is given by :

$C_{eq}=C'+C_3$

$C_{eq}=0.47+1.5$

$C_{eq}=1.97\ \mu F$

So, the equivalent capacitance of the combination is 1.97 micro farad. Hence, this is the required solution.

3 0

3 years ago

Two equal positive charges are held in place at a fixed distance. If you put a third positive charge midway between these two ch

eimsori [14]

Answer:

False

Explanation:

8 0

3 years ago

A+10 u charge and a -10 4C (1 HC - 106 C), at a distance of 0.3 m,

Marina CMI [18]

Answer:

B. Attract each other with a force of 10 newtons.

Explanation:

Statement is incorrectly written. The correct form is: A $+10\,\mu C$ charge and a $-10\,\mu C$ at a distance of 0.3 meters.

The two particles have charges opposite to each other, so they attract each other due to electrostatic force, described by Coulomb's Law, whose formula is described below:

$F = \frac{\kappa \cdot |q_{A}|\cdot |q_{B}|}{r^{2}}$ (1)

Where:

$F$ - Electrostatic force, in newtons.

$\kappa$ - Electrostatic constant, in newton-square meters per square coulomb.

$|q_{A}|,|q_{B}|$ - Magnitudes of electric charges, in coulombs.

$r$ - Distance between charges, in meters.

If we know that $\kappa = 8.988\times 10^{9}\,\frac{N\cdot m^{2}}{C^{2}}$ , $|q_{A}| = |q_{B}| = 10\times 10^{-6}\,C$ and $r = 0.3\,m$ , then the magnitude of the electrostatic force is: