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2 years ago

10

A ball is thrown up with a vertical velocity of 15 m/s and a horizontal velocity of 50 m/s. Calculate how many seconds it will t

ake for it to reach it's peak (assuming no air resistance).

1 answer:

DerKrebs [107]2 years ago

5 0

Answer:

It will take 23 hours and 29 minutes

Explanation:

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Magnetic induction is used for what?

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For radio broadcasting, in electricity meters, in any generator.

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2 years ago

Describe the relationship between a moving objects mass and its kinetic energy

swat32

Kinetic energy is the energy of mass in motion, the kinetic energy that an object has is because of it's motion.Heavier objects that are moving have more kinetic energy than lighter ones.

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2 years ago

A student wants to approximate the amount of work that the force due to gravity does on the student as the student walks up a se

Inessa [10]

Answer:

Options A and D

Explanation:

In this question the student needs to collect these measurements in order to approximate the work done

A. The mass of the student

D. The final vertical height above the initial vertical position.

Workdone = mgh

m = mass

g = gravity = 9.8m/s²

h = vertical height between the initial and the final positions.

The vertical height has to be known as gravity only acts straight down.

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2 years ago

When a current flows through an ionic liquid such as salty water, the moving charges are?

expeople1 [14]

In salty water ions are produced by the salt

here salt is NaCl

so it will break in Na⁺ and Cl⁻

They carry the current

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So current is carrying by ions which are Na⁺ and Cl⁻

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2 years ago

Read 2 more answers

Car A (1750 kg) is travelling due south and car B (1450 kg) is travelling due east. They reach the same intersection at the same

Contact [7]

Consider the east-west direction along x-axis and north-south direction along y-axis. In unit vector notation, velocities can be given as

$\underset{V_{A}}{\rightarrow}$ = velocity of car A before collision = 0 i - $V_{A}$ j

$\underset{V_{B}}{\rightarrow}$ = velocity of car B before collision = $V_{B}$ i + 0 j

$\underset{V_{AB}}{\rightarrow}$ = velocity of combination after collision = (35.8 Cos31.6) i - (35.8 Sin31.6) j = 30.5 i - 18.8 j

$M_{A}$ = mass of car A = 1750 kg

$M_{B}$ = mass of car B = 1450 kg

Using conservation of momentum

$M_{A}$ $\underset{V_{A}}{\rightarrow}$ + $M_{B}$ $\underset{V_{B}}{\rightarrow}$ = ( $M_{A}$ + $M_{B}$ ) ( $\underset{V_{AB}}{\rightarrow}$ )

(1750) (0 i - $V_{A}$ j) + (1450) ( $V_{B}$ i + 0 j) = (1750 + 1450) (30.5 i - 18.8 j)

(1450) $V_{B}$ i - (1750) $V_{A}$ j = 97600 i - 60160 j

Comparing the coefficient of "i" and "j" both side

(1450) $V_{B}$ = 97600 and - (1750) $V_{A}$ = - 60160

$V_{B}$ = 67.3 km/h and $V_{A}$ = 34.4 km/

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2 years ago